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2 years ago

You have 5 cells and they double everyday. How many cells will you have after 8 days

Mathematics

2 answers:

marusya05 [52]2 years ago

8 0

Answer:

Step-by-step explanation:

5 cells x 8 days = 40 cells

your welcome.

Brut [27]2 years ago

6 0

Answer:

$5^{2} (8)$ = 200

Step-by-step explanation:

$5^{2} = 25$
200
In 8 days you will have 200 cells

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I need to know what number goes here? HELP!

Anit [1.1K]

Answer:

Step-by-step explanation:

cross multiply 7/63 by 1/x

so, multiply 7 by x and 63 by 1

you get 63=7x

divide by 7 on both sides and you get 9

3 0

2 years ago

Convertir 0.16 en fracción

MrRa [10]

Answer:

4/25 en forma de fracción

Step-by-step explanation:

7 0

3 years ago

A sample of radium has a weight of 1.5 mg and a half-life of approximately 6 years.

pogonyaev

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

5 0

2 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

2 years ago

Find all exact solutions on the interval 0 ≤ x < 2π.

masya89 [10]

Answer:

View Image

x = π/6, 5π/6, 7π/6, 11π/6

Step-by-step explanation:

The only things you need to know are 2 things:

1.) $csc^2(x)=(csc(x))^2$ , the exponent of trig functions are written in the middle

2.) $csc(x)=\frac{1}{sin(x)}$ , csc() is just the inverse of sin()

3 0

2 years ago