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HACTEHA [7]
3 years ago
15

Evaluate and simplify the following complex fraction

Mathematics
1 answer:
Trava [24]3 years ago
7 0
-5/14!
i hope this helped
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In circle T below, find the measure of angle BEC (This is actually Geometry so..)
ruslelena [56]

Answer:

276.2

Step-by-step explanation:

I just subtracted the totals of AB and DC by 360. It's been a while since I've done this though.

7 0
3 years ago
Triangle DEF has vertices D(0,0), E(7,0), and F(3,7).
Leni [432]

Answer:

(3, 1.7)

Step-by-step explanation:

The point at which the vertices of a triangle meet is known as the orthocenter of the triangle. The orthocenter passes through the vertex of the triangle and is perpendicular to the opposite sides.

Two lines are perpendicular if the product of their slopes is -1.

The slope of the line joining D(0,0), F(3,7) is:

m_1=\frac{7-0}{3-0}=\frac{7}{3}

The slope of the line perpendicular to the line joining D and F is -3/7. The orthocenter is perpendicular to the line joining D and F and passes through vertex E(7, 0). The equation is hence:

y-y_1=m(x-x_1)\\\\y-0=-\frac{3}{7} (x-7)\\\\y=-\frac{3}{7}x+3 \ .\ .\ .\ (1)

The slope of the line joining E(7,0), and F(3,7). is:

m_1=\frac{7-0}{3-7}=-\frac{7}{4}

The slope of the line perpendicular to the line joining E and F is 4/7. The orthocenter is perpendicular to the line joining E and F and passes through vertex D(0, 0). The equation is hence:

y-y_1=m(x-x_1)\\\\y-0=\frac{4}{7} (x-0)\\\\y=\frac{4}{7} x\ .\ .\ .\ (2)

The point of intersection of equation 1 and equation 2 is the orthocenter. Solving equation 1 and 2 simultaneously gives:

x = 3, y = 1.7

4 0
3 years ago
Bir araç 5 saatte 80km yol almaktadır. Buna göre bu aracın hızı kaç m/dk'dır?
8090 [49]
80 km = 80000 m
5 saatte = 300 dk’dir
80000m/300 dk’dir = 266.666667 m/dk’dir
(Yazım yanlışsa kusura bakmayın türkçe bilmiyorum :) )
6 0
2 years ago
Calcule:
zaharov [31]
<span>a. 8                                                                                                                                    b. 20                                       </span><span>                                                                                            c. 4                                                                                                                                     d. 16/5                                                                                                                                 e. 10                                                                                                                                   f.   5                                                                                                                                     g.  2                                                                                                                                     h.  8/3</span>
3 0
3 years ago
Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.
Solnce55 [7]

Answer:

7 digits can be used for each position

There are a total of 5 positions

N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

7 0
3 years ago
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