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RideAnS [48]
3 years ago
12

A pollster contacts 74 people in the 18-21 age bracket and finds that 38 of them respond and 36 refuse to respond. When 297 peop

le in the 22-29 age bracket are contacted, 278 respond and 19 refuse to respond. Suppose that one of the 371 people is randomly selected. Find the probability of getting someone in the 18-21 age bracket OR someone who refused to respond. Round to 3 decimal places.
Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0

Answer:

0,250

Step-by-step explanation:

The probability that you looking for is sum of probability of getting someone in the 18-27age (74 persones) and probability to getting someone who refused (36 and 19 persones) - probability of getting some of 18-27 age who refused (36 persons).

The probability is:

P(a or b)= p(a)+p(b)-p(a&b)=74/371+(36+19)/371-36/371=0,199+0,148-0,097=0,250

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belka [17]

Answer:

With rare exceptions, cars decrease in value with age. Depending on other factors, like accidents, repairs, or other damage, the value of a car may decrease even faster. If you borrowed money to buy a car, you might owe more on your car loan than its current value. When that happens, you have negative equity in the car. Some car dealers say you won’t be responsible for the remaining balance on your old car loan when you trade in your old car. But that might not be true. Dealers sometimes just roll over the negative equity into your new car loan, so you still end up paying it.

Step-by-step explanation:

Say you want to trade in your car for a newer model.

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5 0
3 years ago
The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).
natita [175]

Answer:

68% of jazz CDs play between 45 and 59 minutes.

Step-by-step explanation:

<u>The correct question is:</u> The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).

According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?

Let X = <u>playing time of jazz CDs</u>

SO, X ~ Normal(\mu=52, \sigma^{2} =7)

The z-score probability distribution for the normal distribution is given by;

                                    Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

Now, according to the 68-95-99.7 rule, it is stated that;

  • 68% of the data values lie within one standard deviation points from the mean.
  • 95% of the data values lie within two standard deviation points from the mean.
  • 99.7% of the data values lie within three standard deviation points from the mean.

Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;

   For 45 minutes, z-score is =  \frac{45-52}{7}  = -1

   For 59 minutes, z-score is =  \frac{59-52}{7}  = 1

This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.

6 0
3 years ago
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umka21 [38]

Answer:

D

Step-by-step explanation:

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3 years ago
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Dmitry_Shevchenko [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Answer:

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2(-3) = -6 therefore the answer is -6 hope that helps!

8 0
3 years ago
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