The grams of aluminium extracted from 5000g of alumina is 2647 grams
<h3>Chemical formula of alumina:</h3>
Let's calculate the molecular mass of Al₂O₃
Al₂O₃ = 27 × 2 + 16 × 3 = 54 + 48 = 102 g/mol
Therefore,
102 g of Al₂O₃ = 54 g of aluminium
5000g of Al₂O₃ = ?
mass of aluminium produced = 5000 × 54 / 102
mass of aluminium produced = 270000 / 102
mass of aluminium produced = 2647.05882353
mass of aluminium produced = 2647 grams
learn more on mass here: brainly.com/question/14627327
Question: Given the balanced equation representing a reaction:
2H2 + O2 ==>2H2O
What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of oxygen?
(1) 18 g (3) 56 g
(2) 36 g (4) 72 g
Answer:
"72 gram" is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of oxygen
Explanation:
We will do stoichiometry in this kind of problem:
Therefore, the total mass of water formed is 72 g.
Answer:
the option e is correct I think
The solution is either saturated or supersaturated with solute
<span>Structures that represent 2-methylbutan: a, b, c, d.
</span>a - because methyl group is closer to the right end of butane chain, numbers go from right to left in butane and methyl is on second carbon.
b - because methyl group is closer to the left end of butane chain, numbers go from left to right in butane and methyl is on second carbon.
c - longest chain is butane, from one CH₃ to another CH₃.
d - same as a).