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Len [333]
3 years ago
9

The energies of the bonds broken in a certain reaction are greater than the energies of the bonds formed. Which one of the follo

wing statements about this reaction must be true?
a. The reaction is endothermic.
b. The reaction is exothermic.
c. The reaction is spontaneous.
d. The reaction is non-spontaneous.
Chemistry
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

a. The reaction is endothermic.

Explanation:

The heat involved in a chemical reaction is given by the enthalpy change (ΔH), which is equal to the balance between the chemical bonds that are broken (release energy) and the chemical bonds that are formed (need energy):

ΔH ≅ bonds broken - bonds formed

If broken bonds > bonds formed ⇒ ΔH > 0 ⇒ endothermic reaction

Therefore, the reaction is endothermic (it requires energy).

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3 years ago
What is the molarity of a 5.0 L solution that contains 0.5 moles of KNO3
pashok25 [27]

Answer:

Molarity of a 5.0 L solution that contains 0.5 moles of KNO3 is 0.1 M

Explanation:

Molarity : It is used to express the concentration of the solution and defined as total moles of solute present in one liter of solution .

Molarity =\frac{moles\ of\ solute}{volume\ of\ solution(L)}

Moles of KNO3 = 0.5 (given)

Volume of solution = 5.0 L

Substitute the value in given formula ,

Molarity =\frac{0.5\ moles }{5.0\ L}

on calculation,

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8 0
4 years ago
At a certain temperature the vapor pressure of pure chloroform (CHCl3) is measured to be 91. torr. Suppose a solution is prepare
OleMash [197]

Answer:

P_{CCl_4}=52.43torr

Explanation:

Hello there!

In this case, sine the solution of this problem require the application of the Raoult's law, assuming heptane is a nonvolatile solute, so we can write:

P_{CCl_4}=x_{CCl_4}P_{CCl_4}^{vap}

Thus, we first calculate the mole fraction of chloroform, by using the given masses and molar masses as shown below:

x_{CCl_4}=\frac{140/153.81}{140/153.81+67.1/100.21}=0.576

Therefore, the partial pressure of chloroform turns out to be:

P_{CCl_4}=0.576*91torr\\\\P_{CCl_4}=52.43torr

Regards!

3 0
3 years ago
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