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kap26 [50]
2 years ago
14

Describe each of the following properties of water…

Chemistry
1 answer:
Allushta [10]2 years ago
5 0

Cohesion – The attraction of water molecules to each other and creates high surface tension in water. An example of how it helps support life on Earth is that it allows insects to walk across the surface.

Adhesion – The attraction of water molecules to other substances and allows water to travel against gravity. An example of this is water moving up a tree even when there is gravity.

Specific heat capacity – the heat required to raise the temperature of the unit mass of a given substance by a given amount. An example of this is a swimming pool staying the same temperature no matter if it is hot or cold outside.

Expansion upon freezing – Water expands when its frozen which will keep it from sinking. Floating ice keeps the water underneath it warm. An example of this is an iceberg floating on top of a body of water.

Universal solvent – Can dissolve almost anything, usually water. An example is that water transports important chemicals or nutrients/minerals that is needed for all living organisms.

I just learned about this lol...

Hope this helps UwU

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Answer:

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Explanation:

The key difference between Democritus and Dalton atomic theory is that the Democritus atomic theory is an ancient theory that scientists later refined and elaborated whereas Dalton atomic theory is a comparatively modern, scientific theory that we cannot discard due its important statements.

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Is CO2 a compound, molecule, or atoms/elements?
Lunna [17]

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4 0
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Calculate the pH of a 0.50 M HIO. The Ka of hypoiodic acid, HIO, is 2.3x10–11.0.305.325.479.474.80
never [62]

Answer:

pH = 5.47

Explanation:

The equilibrium that takes place is:

HIO ↔ H⁺ + IO⁻

Ka = \frac{[H+][IO-]}{[HIO]} = 2.3 * 10⁻¹¹

At equilibrium:

  • [HIO] = 0.5 M - x
  • [H⁺] = x
  • [IO⁻] = x

<u>Replacing those values in the equation for Ka and solving for x:</u>

Ka=\frac{x^2}{0.5-x}=2.3*10^{-11} \\x^2=(2.3*10^{-11})(0.5-x)\\x^2=1.15*10^{-11}-2.3*10^{-11}x\\x^2+2.3*10^{-11}x-1.15*10^{-11}=0\\x=3.39*10^{-6}

Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47

7 0
3 years ago
You have at your disposal 3 1-pound bags of various pure salts that dissolve readily in water. You can add one of the bags to a
Sedaia [141]

Answer:

This question appears incomplete

Explanation:

However, it should be noted that addition of soluble salts generally lowers the freezing point of water hence after the addition, water will no longer freeze at 0°C but lower.

Soluble salts tend to form more ions in water, it is these ions that are responsible for interfering with the hydrogen bonds hence lowering the freezing. Thus, (since each bag are of the same weight) <u>the bag that contains the salt that ionizes more in water will lower the freezing point by the greatest amount</u>.

NOTE: Different weight of the salts could lead to more ions been formed in the water by some salts as against the other.

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What is the density of a plastic ball that has a volume of 6cm) and a mass of 12g?<br> 50 cm3
marissa [1.9K]

Answer:

2 g/cm³

Explanation:

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