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3 years ago

Why wasn't oxidation type chemical weathering common more than 2 billion years ago?

Chemistry

1 answer:

scZoUnD [109]3 years ago

6 0

Answer:

Due to deficiency of Oxygen in atmosphere.

Explanation:

Oxidation is defined in two ways, 1) The addition of Oxygen and Removal of Hydrogen 2) The removal of electrons.

We will discuss the first definition for this question. The addition of oxygen to various compounds results in the oxidation of that compound.

Example: Oxidation of Methane;

CH₄ + 2 O₂ → CO₂ + 2 H₂O

In this example oxygen is added to methane and hydrogen is being removed from methane.

Oxidation type chemical weathering common more than 2 billion years ago because of less amount of Oxygen in atmosphere and the oxygen which was produced by plants reacted with different metals like Iron forming precipitates which precipitated to the bottom of oceans.

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How many grams of oxygen are required to react with 12.0 grams of octane(C8H18) in the combustion of octane in gasoline?

solniwko [45]

Answer : 42 grams of oxygen are required.

Explanation :

Step 1 : Write balanced chemical equation.

The combustion reaction of octane with oxygen can be written as,

$2 C_{8}H{18} (g) + 25 O_{2} (g) \rightarrow 16 CO_{2} (g) +18 H_{2}O (g)$

Step 2 : Find moles of octane.

The given mass of octane is 12 g

Molar mass of octane is 114.2 g/mol

The moles of octane are calculated as,

$moles =\frac{grams}{MolarMass} =\frac{12g}{114.2g/mol} = 0.105 mol$

We have 0.105 mol octane.

Step 3: Use mole ratio from balanced equation to find moles of O₂

The mole ratio of octane and O₂ is 2 : 25. Let us use this as a conversion factor.

$0.105 mol C_{8}H_{18} \times\frac{25mol O_{2}}{2molC_{8}H_{18}} = 1.31 mol$

We have 1.31 mol O₂.

Step 4 : Convert moles of O₂ to grams.

The molar mass of O₂ is 32 g/mol.

The grams of O₂ can be calculated as,

$1.31 mol O_{2} \times\frac{32g}{mol} = 42 grams$

42 grams of oxygen are required.

8 0

3 years ago

H. Identity of unknown metal

OLEGan [10]

Answer:

you can identify an unknown substance by measuring its density and comparing your results to a list of known densities. Density=mass/volume. Assume that you have to identify an unknown metal. You can determine the mass of the metal on a scale.

8 0

4 years ago

Identify the gas law that applies to the following scenario: A 36.5 liter balloon holding 2.9 moles of carbon dioxide leaks. If

jarptica [38.1K]

Answer:

Avogadro's Law; 15.1L

Explanation:

Boyle's Law- Pressure and volume are inversely related, so an increase in pressure= decrease in volume. We see this in the equation P1V1=P2V2.

Charle's Law- Gas expands/increases in volume when temperature increases, so they are proportional. We see this in the formula $\frac{V1}{T1} = \frac{V2}{T2}$ .

Guy-Lussac's Law- As temperature increases, pressure increases, so they are proportional. We see this in the formula $\frac{P1}{T1} = \frac{P2}{T2}$ .

Avogadro's Law- There are equal amount of volume have an equal amount of moles, so they are proportional. We see this in the formula $\frac{V1}{n1} = \frac{V2}{n2}$ .

Plugging in the values based on Avogadro's Law, we'll have:

$\frac{36.5}{2.9} = \frac{V2}{1.2}$

12.6 = $\frac{V2}{1.2}$

12.6 x 1.2 = V2

15.1L =V2

6 0

3 years ago

ANSWER THIS QUESTION FOR 29 POINTS

elena-14-01-66 [18.8K]

Answer:

Explanation:

cells process rna and trna

converting food into energy

the regrowth of cells that have died through out the day

the transcription of dna to rna

hope this helped :)

4 0

3 years ago

What are the products in the following chemical reaction?

hodyreva [135]

The products are on the right side of the chemical equation, while the reactants are on the left side of the chemical equation.

Therefore if we have:

methane + oxygen → carbon dioxide + water

Then the reactants are methane + oxygen

The products are: A) Carbon dioxide + Water

4 0

3 years ago