Answer:
32.7 g of Zn
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Zn + 2HCl —> ZnCl₂ + H₂
From the balanced equation above,
1 mole of Zn reacted to produce 1 mole of H₂
Next, we shall determine the number of mole of Zn required to produce 0.5 mole of H₂. This can be obtained as follow:
From the balanced equation above,
1 mole of Zn reacted to produce 1 mole of H₂.
Therefore, 0.5 mole of Zn will also react to produce to 0.5 mole of H₂.
Thus, 0.5 mole of Zn is required.
Finally, we shall determine the mass of 0.5 mole of Zn. This can be obtained as follow:
Mole of Zn = 0.5 mole
Molar mass of Zn = 65.4 g/mol
Mass of Zn =?
Mass = mole × molar mass
Mass of Zn = 0.5 × 65.4
Mass of Zn = 32.7 g
Thus, 32.7 g of Zn is required to produce 0.5 mole of H₂.
Answer:
Amount of Na = 2.17moles
Explanation:
Mass of Na = 50g
Molar mass of Na = 23g/mol
Amount of mole = mass/molar mass
Amount of mole = 50/23
Amount of mole = 2.17moles
Answer: The total pressure will be 1,11,720 torr.
Explanation:
Partial pressure of nitrogen gas.
(1atm = 760 torr)
Partial pressure of oxygen gas,
Total pressure, in torrs, of the scuba gas mixture = 40280 + 71440 torr =111,720 torr
Hence , the total pressure in scuba gas mixture is 111,720 torr.
Explanation:
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