Answer:
[293.21;372.28]
Step-by-step explanation:
Hello!
You are asked to construct a 90% Confidence Interval for the mean duration of the foreclosure process in Boston.
The Study variable is X: duration of foreclosure in Boston. X≈N(μ;σ²)
Sample n=8
To study the population sample you can use either a Z or a t-statistic. Since the sample is less than 10, I'll choose a Student t-statistic, because it is more potent with small samples than the Z, but either one is a good choice.
X[bar]= 332.75
S= 59.01
[293.21;372.28]
With a confidence level of 90% you'd expect the interval [293.21;372.28] to contain the population mean of the duration of the foreclosure process in Boston.
I hope you have a SUPER day!
if its diameter is 8 cm, then its radius is half that, or 4 cm.
Answer:
197
Step-by-step explanation:
Sample proportion is; p^ = 12/50 = 0.24
Margin of error of 5% is given by the formula;
ME = (z_0.05) √[p^(1 - p^)/n]
Let's make n(number of sample) the subject.
n = ((z_0.05)/ME)²((p^)(1 - p^))
From tables, the z-score of 0.05 is 1.645
Thus;
n = ((1.645)/0.05)²(0.24(1 - 0.24))
n ≈ 197
Answer:
yes
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
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