<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890
:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s =
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
Answer:
see the explanation
Step-by-step explanation:
In this problem
I will assume that the total amount required for the trip is $1,200
so
Let
x ----> the number of weeks
we know that
The number of weeks multiplied by $75 plus $300 must be at least $1,200
In this context, the term "at least" means "greater than or equal to"
so
The linear inequality that represent this problem is

Solve for x
subtract 300 both sides


Divide by 75 both sides

therefore
The minimum number of weeks you need to save is 12
I think 2 equal ratios are called a <u>proportion</u>
Answer:
1872
Step-by-step explanation:on edge
Similarities: same atomic number
Differences: they have a different number of neutrons