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NeX [460]
3 years ago
15

Which are parts of a neuron?

Physics
1 answer:
otez555 [7]3 years ago
3 0
Axon
Dendrites
Myelin sheath
I think that those are enough
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How does end A of the rod react when the charged ball approaches it after a great many previous contacts with end A? Assume that
sleet_krkn [62]

Answer: IT IS STRONGLY REPELLED

Explanation: The laws of guiding magnetic attraction or repulsion of Magnetic materials,states that when like poles are brought together they repel each other, but when unlike poles are brought together they are attracted.

The rod will be strongly repelled because the forces on the rod is greater and has the same Polarity as the charged ball.

6 0
3 years ago
Consider a point 0.5 m above the midpoint of the two charges. As you can verify by removing one of the positive charges, the ele
yKpoI14uk [10]

Answer:

the magnitude of the total electric field is 25 V/m

Explanation:

Given data

point above = 0.5 m

charges = 18 V/m

to find out

the magnitude of the total electric field

solution

the magnitude of the total electric field is 25 V/m because number is less than    the twice magnitude of field by every charge and  the horizontal component in electric field by every charge cancel out and vertical component in field added together

6 0
3 years ago
Does thermal energy flow from warmer objects to cooler objects
jolli1 [7]

Answer:yes

Explanation:

Thermal energy is the sum of all kinetic and potential energy in a substance. He is the thermal energy that flows from a warmer object to a cooler object.

8 0
3 years ago
Read 2 more answers
You are traveling at 55 mi/h along the x-axis relative to a straight, level road and pass a car that is traveling at 45 mi/h. Th
Alik [6]

Answer:

10 mph

Explanation:

55 - 45 = 10 mph

4 0
2 years ago
A ball on the end of a string is whirled around in a horizontal circle of radius 0.478 m. The plane of the circle is 1.02 m abov
m_a_m_a [10]

Answer:

Explanation:

We shall find first the velocity of ball at the time when string breaks. Let it be v . During its fall on the ground , 1.02 m below, we use the formula

h = 1/2 gt² where t is time of fall .

1.02 = 1/2 x 9.8 x t²

t²= .2081

t = .456

During this time it travels horizontally at distance of 2.5 m with uniform velocity of v

v x .456 = 2.5

v  = 5.48 m /s

centripetal acceleration

= v² / r where r is radius of the circular path

= 5.48² / .478

= 62.82 m /s²

3 0
3 years ago
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