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11Alexandr11 [23.1K]
3 years ago
9

Which goes into which category?

Physics
1 answer:
Pavel [41]3 years ago
6 0

Evidence of Chemical Change:

A car rusting

Leaves changing in October

The glow of a light bulb

A white cloudy substance occurs after mixing two substances

Burning toasts

A candle being lit

Evidence of Physical Change:

Water boiling

Yellow and blue paints mixed together

Wax melting

Crushing a rock with a hammer

Hope this helps!

Have a great day!

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3. Which of the following processes provides the water necessary for human consumption?
hram777 [196]

Answer:

precipitation is the answer..

Explanation:

precipitation is any product of the condensation of atmospheric water vapor that falls under gravitational pull from clouds. The main forms of precipitation include drizzling, rain, sleet, snow, ice pellets, graupel and hail.

6 0
3 years ago
Read 2 more answers
A truck moving at 45 m/s passes a police car moving at 36 m/s in the opposite direction. if the frequency of the siren is 500 Hz
elena-14-01-66 [18.8K]

Answer: observed frequency (f') = 511.97Hz

Explanation: when there is a relative motion between an observer and a sound source, the frequency of sound wave perceived by the observer is different from the frequency of originally sent out by the sound source.

This is called Doppler effect and given mathematically below as

f' = (v + v') /(v- vs) * f

f' = observed frequency

v = speed of sound in air = 340m/s

v' = velocity of observer= 45m/s

vs = velocity of source relative to observer = - 36m/s ( the negative sign came as a result of the fact that the velocity of the source is in opposite direction to the velocity of the observer)

f = original frequency of sound source = 500Hz

f' = (340 + 45)/{340 -(-36)} * 500

f' = 385/ (340 + 36) * 500

f' = 385/ 376 * 500

f' = 1.0239 * 500

f' = 511.97Hz

7 0
3 years ago
An ostrich lays the largest bird egg. A typical diameter for an ostrich egg at its widest part (diameter) is 12 cm (0.12 m). Sup
Vanyuwa [196]

The centripetal acceleration is the ratio of the tangential speed and the

radius of the shell.

The tangential speed of the part of the shell is approximately <u>0.12961 m/s</u>

Reasons;

The widest diameter of the egg, d = 12 cm = 0.12 m

The given centripetal acceleration, a_c = 0.28 m/s²

Required:

The tangential speed of the bird.

Solution;

\displaystyle Centripetal \ acceleration, \ a_c = \mathbf{\frac{v^2}{r}}

Where;

\displaystyle r = The \ radius \ of \ the \ egg \ shell = \frac{d}{2}

v = The tangential speed

Which gives;

\displaystyle r = \frac{0.12}{2} = 0.06

\displaystyle 0.28 \, m/s^2 = \frac{v^2}{0.06 \, m}

v² = 0.28 m/s² × 0.06 m = 0.0168 m²/s²

v = √(0.0168 m²/s²) ≈ 0.12961 m/s

The tangential speed, v = <u>0.12961 m/s</u>

<u />

Learn more about centripetal acceleration here:

brainly.com/question/79801

8 0
3 years ago
calculate the energy spent on spraying a drop of mercury of 1 cm radius into 10^6 droplets all of same radius. surface tension o
WARRIOR [948]

Answer:

ANS : .Energy spent on spraying =4.3542*10^{-4}J

Explanation:

<em>Given:</em>

  • <em>Radius of mercury = 1cm initially ;</em>
  • <em>split into 10^{6} drops ;</em>

Thus, volume is conserved.

i.e ,

\frac{4}{3} \pi R_{o}^{3} = 10^{6}*\frac{4}{3} \pi R_{n}^{3}\\R_{n}=\frac{R_{o}}{10^{2}} = \frac{1cm}{100} = 0.01 cm

  • Energy of a droplet = TΔA

Where ,

  • <em>T is the surface tension </em>
  • <em>ΔA is the change in area</em>

Initial energy E_{i} = T*A_{i}\\= 0.0035 * 4 *\pi *0.01^{2}\\=4.398*10^{-6}J

Final energy E_{f}=10^{6}*T*A_{f}\\=10^{6}*0.0035*4*\pi *(0.0001)^2\\=4.39823*10^{-4}

∴  .Energy spent on spraying = =E_{f}-E{i}\\=(439.823-4.39823)*10^{-6}\\=4.3542*10^{-4}J

ANS : .Energy spent on spraying =4.3542*10^{-4}J

6 0
3 years ago
An object moves in uniform circular motion at 25 m/s and takes 1.0 second to go a quarter circle. Calculate the centripetal acce
tekilochka [14]

Given:

Object in circular motion 25 m/s

1 second to go quarter circle

Required:

Centripetal acceleration:

Solution:

Acceleration = v2/r

Where v is the velocity and r is the radian

Substituting the values into the equation,

Acceleration = v2/r = (25 m/s)2/(4*pi/180) = 8952.47 m2/s2

4 0
3 years ago
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