Answer:
a) 17.33 V/m
b) 6308 m/s
Explanation:
We start by using equation of motion
s = ut + 1/2at², where
s = 1.2 cm = 0.012 m
u = 0 m/s
t = 3.8*10^-6 s, so that
0.012 = 0 * 3.8*10^-6 + 0.5 * a * (3.8*10^-6)²
0.012 = 0.5 * a * 1.444*10^-11
a = 0.012 / 7.22*10^-12
a = 1.66*10^9 m/s²
If we assume the electric field to be E, and we know that F =qE. Also, from Newton's law, we have F = ma. So that, ma = qE, and E = ma/q, where
E = electric field
m = mass of proton
a = acceleration
q = charge of proton
E = (1.67*10^-27 * 1.66*10^9) / 1.6*10^-19
E = 2.77*10^-18 / 1.6*10^-19
E = 17.33 V/m
Final speed of the proton can be gotten by using
v = u + at
v = 0 + 1.66*10^9 * 3.8*10^-6
v = 6308 m/s
Answer:
<h2>640N/cm^2</h2>
Answer D is correct
Explanation:
hope this helps
brainliest appreciated
good luck! have a nice day!
Answer:
move
Explanation:
i think that is it
as plates move large blocks of crust move along the faults
You just pointed out that the gravitational force also depends
on the distance from the planet's center. The radius of Uranus
is about 4 times the Earth's radius. That fact alone means that
the gravitational force on the surface is 1/4² = 1/16 its value on
Earth's surface. So increasing the planet's mass by a factor of
14 doesn't compensate for the 1/16 reduction, and the gravitational
force on Uranus is less than on Earth.
