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melamori03 [73]
3 years ago
5

The eighth-graders at the middle school are going on a field trip to the

Mathematics
1 answer:
Marianna [84]3 years ago
7 0

Answer:

51 minutes per exhibit

Step-by-step explanation:

You might be interested in
A. What is the probability that this couple spends 45 dollars or more?
guapka [62]

Using the probability table, it is found that:

  • a) There is a 0.25 = 25% probability that this couple spends 45 dollars or more.  
  • b) The expected amount the couple actually has to pay is $36.85.

Item a:

To find the probabilities involving the total cost, we have to <u>add the variables X and Y</u> from the table, then:

P(X = 30) = P(X = 15|Y = 15) = 0.2

P(X = 35) = P(X = 15|Y = 20) + P(X = 20|Y = 15) = 0.15 + 0.15 = 0.3

P(X = 40) = P(X = 15|Y = 25) + P(X = 20|Y = 20) + P(X = 25|Y = 15) = 0.05 + 0.15 + 0.05 = 0.25

P(X = 45) = P(X = 20|Y = 25) + P(X = 25|Y = 20) = 0.1 + 0.1 = 0.2

P(X = 50) = P(X = 25|Y = 25) = 0.05

The probability involving <u>values of 45 or more</u> is:

P(X \geq 45) = P(X = 45) + P(X = 50) = 0.2 + 0.05 = 0.25

0.25 = 25% probability that this couple spends 45 dollars or more.

Item b:

For a <em>discrete distribution</em>, the expected value is the <u>sum of each outcome multiplied by it's respective probability</u>, hence, involving the 10% discount for prices above $45:

E(X) = 0.2(30) + 0.3(35) + 0.25(40) + 0.9[0.2(45) + 0.05(50)] = 36.85

The expected amount the couple actually has to pay is $36.85

A similar problem is given at brainly.com/question/25782059

8 0
2 years ago
It’s timed please help
love history [14]

Answer:

4 is included in the domain

Step-by-step explanation:

6 0
3 years ago
Please help!!!
shtirl [24]

Answer:

v = k/p

where k is constant

3.5 = k/5

k = 3.5 × 5

k = 17.5

v = 17.5/p

v= 17.5/8

v = 2.1875

v ≈ 2.20 litres

6 0
3 years ago
What are the degrees of freedom for Student's t distribution when the sample size is 19? d.F. = Use the Student's t distribution
liq [111]

Answer:

a) 18

b) 2.101

Step-by-step explanation:

a) What are the degrees of freedom for Student's t distribution when the sample size is 19?

Degrees of freedom = n - 1

Where n = sample size

= 19 - 1

= 18

b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.

(Round your answer to three decimal places.)

We would be determining these using the t distribution table

1 - 0.95 = 0.05 ( for two tailed)

Or

0.05/2 = 0.025(one - tailed)

Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101

7 0
4 years ago
What is the shape of a cross section that is perpendicular to the base of a cylinder?
Serjik [45]
A.) rectangle would be the correct answer
7 0
4 years ago
Read 2 more answers
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