Colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
ber of bacteria doubles every 2 hours. Jaquan starts with 80 of a different type of bacteria that doubles every 3 hours.
Let x equal number of days.
Colby’s experiment follows the model:
1) y=50*2^x
2) y=50*2^8x
3) y=50*2^12x
Jaquan’s experiment follows the model:
1) y=80*2x
2) y=80*2^8x
3) y=80*2^12x
20 POINTS*****
1 answer:
Answer:
3) y = 50 * 2¹²ˣ
2) y = 80 * 2⁸ˣ
Step-by-step explanation:
1 day = 24 hours
Number of 2-hour periods in 1 day = 24 ÷ 2 = 12
Number of 3-hour periods in 1 day = 24 ÷ 3 = 8
Colby's experiment:
y = 50 * 2¹²ˣ
Jaquan's experiment:
y = 80 * 2⁸ˣ
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i do not remember how to solve this but i just answered a question that had this problem in it on my algebra test and that is the right answer
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