Question

What is the final velocity of an object that is dropped if it falls a distance of 100 m?

Answer 1

Answer:

$44.27m/s$

Explanation:

The kinematic equation

$v_f^2=v_0^2+2ad$

gives the final velocity $v_f$ of the object given the initial velocity $v_0$, the acceleration $a$, and the distance traveled $d$.

For our case, the object is dropped; therefore,

$v_0=0$

I.e. the initial velocity is zero. The acceleration due to gravity is

$a=9.8m/s^2$,

and the distance traveled is $d=100m$.

Putting the values into the equation we get:

$v_f^2=0+2(9.8ms^{-2})(100m)\\\\v_f^2=1960\\\\v_f=\sqrt{1960} \\\\\boxed{v_f=44.27m/s}$

The final velocity of the object is 44.27 m/s.