What information did mendeleev have about the elements he organized into a periodic table

g Determine the magnetic field midway between two long straight wires 2.0 cm apart in terms of the current I in one when the oth

MrMuchimi

Answer:

$B_{net}$ = $(2\times 10^{-5}T/A).(I-25A)$

Explanation:

Given :

the distance between the two wires is = 2 cm

= 0.02 m

Current in one of the wire, I = 25 A

Now we know that, when the direction of the current is same that is in one direction , the magnetic field at the mid point in between the two wires will oppose each other.

Therefore we know that

$B_{net}$ = $\frac{\mu _{o}\times I_{1}}{2\pi r_{1}}-\frac{\mu _{o}\times I_{2}}{2\pi r_{2}}$

= $\frac{(4\pi \times 10^{-7}T.m/A)}{2\pi (1\times 10^{-2}m)}\times (I-25A)$

= $(2\times 10^{-5}T/A).(I-25A)$

4 0

3 years ago

Two spherical asteroids have the same radius R. Asteroid 1 has mass M and asteroid 2 has mass 1.97·M. The two asteroids are rele

nekit [7.7K]

Answer:

$0.536\sqrt{\frac{GM}{R}}$

Explanation:

We are given that

Mass of one asteroid 1, $m_1=M$

Mass of asteroid 2, $m_2=1.97 M$

Initial distance between their centers,d=13.63 R

Radius of each asteroid=R

d'=R+R=2R

Initial velocity of both asteroids

$u=0$

We have to find the speed of second asteroid just before they collide.

According to law of conservation of momentum

$(m_1+m_2)u=m_1v_1+m_2v_2$

$(M+1.97 M)\times 0=Mv_1+1.97Mv_2$

$Mv_1=-1.97 Mv_2$

$v_1=-1.97v_2$

According to law of conservation of energy

$Gm_1m_2(\frac{1}{d'}-\frac{1}{d})=\frac{1}{2}m_1v^2_1+\frac{1}{2}m_2v^2_2$

$GM(1.97M)(\frac{1}{2R}-\frac{1}{13.63R})=\frac{1}{2}M(-1.97v_2)^2+\frac{1}{2}(1.97M)v^2_2$

$1.97M^2G(\frac{13.63-2}{27.26R})=\frac{1}{2}Mv^2_2(3.8809+1.97)$

$1.97MG(\frac{11.63}{27.26 R})=\frac{1}{2}(5.8509)v^2_2$

$v^2_2=\frac{1.97GM\times11.63\times 2}{27.26R\times 5.8509}$

$v_2=\sqrt{\frac{1.97GM\times11.63\times 2}{27.26R\times 5.8509}}$

$v_2=0.536\sqrt{\frac{GM}{R}}$

Hence, the speed of second asteroid = $0.536\sqrt{\frac{GM}{R}}$

8 0

3 years ago

Give proof that mass is constant and weight keeps changing.

shutvik [7]

The mass of an object stays the same wherever it is, but its weight can change. This happens if the object goes where the gravitational field strength is different from the gravitational field strength on Earth, such as into space or another planet.

7 0

2 years ago

PLS HELP ASAP!!! <br> I don’t understand this at all

Mnenie [13.5K]

Answer:

The part that completes the nuclear equation is:

$^{221}_{87}Fr$

Explanation:

<h2>A) Preliminar explanation</h2>

The <em>nuclear equation</em> represents a nuclear reaction: the change of the nucleus of an atom.

The given equation represents an actinium atom releasing an alpha particle.

This is the meaning of each part of the equation:

Ac is the chemical symbol of actinium
The superscript to the left of the chemical symbol is the mass number of the atom (number of protons plus number of neutrons). The mass number is 225.
The subscript to the left of the chemical symbol is the atomic number of the atom (number of protons). The atomic number is 89.

$^4_2He$ is the symbol of the alpha particle. It is an atom of helium
The mass number is 4
The atomic number is 2

<h2>B) Solution</h2>

To <em>complete the nuclear equation </em>you must do two balances: mass number balance and atomic number balance.

<u>i) Mass number balance</u>

225 = A + 4 ⇒ A = 225 - 4 = 221

<u>ii) Atomic number balance</u>

89 = Z + 2 ⇒ Z = 89 - 2 = 87

Therefore, the mass number of the unknown atom is 221, and the atomic number is 87.

From a periodic table, the element with atomic number 87 is francium, Fr.

Now, you have the chemical symbol, the atomic number, and the mass number of the unknown atom, which lets you to write the atom that completes the <em>nuclear equation</em>.

$^{221}_{87}Fr$

7 0

3 years ago

Increase the mass of the beanbag its gravitational potential energy will

kotegsom [21]

The gravitational potential energy will increase

Explanation:

The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in a gravitational field.

Near the Earth's surface, the GPE of an object is given by

$GPE=mgh$

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object above the ground

From the equation, we see that the GPE is directly proportional to the mass: therefore, if the mass increases, the GPE will increase as well.

So, for the beanbag in this problem, when its mass increases, the GPE will increase as well.

Learn more about gravitational potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

5 0

3 years ago