All categories

3 years ago

Kayla drew two ray diagrams to compare the behavior of light rays.

Physics

2 answers:

Naddika [18.5K]3 years ago

8 0

The answer is the last option

Explanation:

blsea [12.9K]3 years ago

8 0

Answer:

D.) Diagram X shows refraction from a denser to a less dense medium, and diagram Y shows reflection.

Explanation:

As per ray diagram we can see that light ray moves from one medium to another medium

So this must be the phenomenon of refraction of light

Now in this phenomenon of light we can see that initially light makes small angle with the normal

After moving into the other medium the light makes more angle with the normal

so here light is bending away from the normal when it is moving into the other medium

So here light is moving into less denser medium from denser medium

So correct answer must be

D.) Diagram X shows refraction from a denser to a less dense medium, and diagram Y shows reflection.

You might be interested in

You pull with a force of 77 N on a piece of luggage of mass 23 kg, but it does

Vinvika [58]

Answer:

The force of static friction acting on the luggage is, Fₓ = 180.32 N

Explanation:

Given data,

The mass of the luggage, m = 23 kg

You pulled the luggage with a force of, F = 77 N

The coefficient of static friction of luggage and floor, μₓ = 0.8

The formula for static frictional force is,

Fₓ = μₓ · η

Where,

η - normal force acting on the luggage 'mg'

Substituting the values in the above equation,

Fₓ = 0.8 x 23 x 9.8

= 180.32 N

Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N

5 0

3 years ago

Read 2 more answers

A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 60.0 m/s , and it leav

nata0808 [166]

Answer:

F = -307.4 N

Explanation:

It is given that,

Mass of the baseball, m = 0.145 kg

Initial speed of the baseball, u = 60 m/s

Final speed of the baseball, $v=65\ cos(30)=56.29\ m/s$

Time of contact, $t=1.75\ ms=1.75\times 10^{-3}\ s$

(a) It is assumed to find the horizontal component of average force. It is given by :

$F=m\dfrac{v-u}{t}$

$F=0.145\dfrac{56.29-60}{1.75\times 10^{-3}}$

F = -307.4 N

So, the horizontal component of average force is 307.4 N. Hence, this is the required solution.

8 0

3 years ago

Consider a 100 g object dropped from a height of 1 m. Assuming no air friction (drag), when will the object hit the ground and a

Katyanochek1 [597]

Answer:

speed and time are Vf = 4.43 m/s and t = 0.45 s

Explanation:

This is a problem of free fall, we have the equations of kinematics

Vf² = Vo² + 2g x

As the object is released the initial velocity is zero, let's look at the final velocity with the equation

Vf = √( 2 g X)

Vf = √(2 9.8 1)

Vf = 4.43 m/s

This is the speed with which it reaches the ground

Having the final speed we can find the time

Vf = Vo + g t

t = Vf / g

t = 4.43 / 9.8

t = 0.45 s

This is the time of fall of the body to touch the ground

3 0

3 years ago

A proton with charge 1.601019 As is moving at 2.4105 m/s through a magnetic field of 4.5 T. You want to find the force on the pr

Whitepunk [10]

The force on the proton is 17.4 N.

<h3>What is the force on the proton?</h3>

Now we know that the proton is positively charged and that the force on the charge as it moved through the magnetic field could be given by the relation; F = qvB

Where;

F = force

q = charge

v = velocity

B = magnetic field

Having said this, we can see that;

q = 1.601019 As or C

v = 2.4105 m/s

T = 4.5 T

F = 1.601019 As * 2.4105 m/s * 4.5 T

F = 17.4 N

Learn more about magnetic force:brainly.com/question/12824331

#SPJ1

6 0

1 year ago

A car traveled 112.0m in 24.500s, what was a car’s average speed?

kodGreya [7K]

Average speed of the car is 4.57 m/s

Explanation:

Speed is calculated by the rate of change of displacement.

It is given by the formula, Speed = Distance/Time

Here, distance = 112 m and time = 24.5 s

Speed of the car = 112/24.5 = 4.57 m/s

3 0

3 years ago