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4 years ago

Identify any solutions to the system given below. 2x + y = 5 3y = 15 – 6x (6, –7) (2, 1) (–2, –9) (–4, 13)

Mathematics

2 answers:

sashaice [31]4 years ago

8 0

Answer:

The answer (2, 1), (-4,13), (6,-7)

Step-by-step explanation:

Consider 2x+y=5 as equation 1, and 3y=15-6x as equation 2

1. Substituting values x and y with x=2 and y=1 as given by the coordinates (2,1)

Equation 1

2(2)+1=5 therefor it holds

Equation 2

3(1)=15-(6×2) also holds

2. Substituting values x and y with x=6 and y=-7 as given by the coordinates (6,-7)

Equation 1

2(6)+(-7)=5

5=5 holds

Equation 2

3(-7)=15-(6×6)

-21=-21 also holds

3. Substituting values x and y with x=-4 and y=13 as given by the coordinates (-4,13)

Equation 1

2(-4)+13=13-8=5 holds

Equation 2

3(13)=15-(6×-4)=39 also holds

4. Substituting values x and y with x=-2 and y=-9 as given by the coordinates (-2,-9)

Equation 1

2(-2)+(-9)=-4-9=-13≠5 does not hold

Equation 2

3(-9)≠15-(6×-2)

-27≠27 does not hold

The coordinates (2,1), (-4,13) and (6,-7) can be used as solutions to the system given

fomenos4 years ago

8 0

Answer:

(6,-7) (2,1) (-4,13)

Step-by-step explanation:

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IgorC [24]

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Step-by-step explanation:

step 1

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we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

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we have

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substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

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Step-by-step explanation:

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