Answer:
The answer would be 3.2, since .2 is equivalent to 1/5 ^^
Answer:
Height = 3v/y² units
StartFraction 3 V Over y squared EndFraction units
Step-by-step explanation:
The volume of a solid right pyramid with a square base is v units3 and the length of the base edge is y units. which expression represents the height of the pyramid? units (3v – y2) units (v – 3y2) units units
Volume of a solid right pyramid = 1/3 × area of the base × height
Volume of a solid right pyramid = v units³
Area of the base = y² unit²
Volume of a solid right pyramid = 1/3 × area of the base × height
v = 1/3 × y² × height
Height = v ÷ 1/3 × y²
= v × 3/1y²
= (v × 3) / y²
= 3v / y²
Height = 3v/y² units
StartFraction 3 V Over y squared EndFraction units
2.8 meter= 2800cms
To solve this, we can create a simple algebraic equation:
45x=2800
Divide both sides by 45.
(45x)/45=(2800)/45
x=62.222
You can make 62 full pieces.
To find the waste, multiply the numbers of pieces by the length of each.
62*45
=2790
2800-<span>2790
=10 centimeters
There would be 10 centimeters of wasted linen.
Hope this helps!
-Benjamin</span>
Answer:
A. only II
Step-by-step explanation:
Mathematics calculus differentiates things into discrete and continuous. Discrete things have indivisible units, the example will be how many dogs in a village. There is no half dog, it's either one, two, etc. But the distance covered by train can be written as half miles, it's divisible unit.
The number of books and bracelets also discrete, thus the answer is A.
Answer:
or
.
Step-by-step explanation:
We have been given that Nigel is planning his training schedule for a marathon over a 4-day period. He is uncertain how many miles he will run on two days. One expression for the total miles he will run is
.
The Commutative Property of Addition states that we can add numbers in any order. For example a and b be two numbers.
According to Commutative Property of Addition
.
Similarly, we can write an equivalent expression to our given expression as:

We can simplify our expression as:
.
Therefore, our required expression would be
or
.