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Ket [755]
3 years ago
14

Suppose you read in the newspaper that a new planet has been found. Its average speed in its orbit is 33 kilometers per second (

km/s). When it is closest to its star, it moves at 31 km/s, and when it is farthest from its star, it moves at 35 km/s. This story is in error because
Choose one:
A. Kepler's third law says the planet has to sweep out equal areas in equal times, so
the speed of the planet cannot change.
B. the average speed is too fast.
C. using these numbers, the square of the orbital period will not be equal to
the cube of the semimajor axis.
D. planets stay at a constant distance from their stars; they don't move closer or farther away.
E. Kepler's second law says the planet must move fastest when it is closest, not
when it is farthest away.
E. Kepler's second law says the planet must move fastest when it is closest, not
when it is farthest away.
Physics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

E. Kepler's second law says the planet must move fastest when it is closest, not  when it is farthest away.

Explanation:

We can answer this question by using Kepler's second law of planetary motion, which states that:

"A line connecting the center of the Sun with the center of each planet sweeps out equal areas in equal intervals of time"

This means that when a planet is further away from the Sun, it will move slower (because the line is longer, so it must move slower), while when the planet is closer to the Sun, it will move faster (because the line is shorter, so it must move faster).

In the text of this problem, it is written that the planet moves at 31 km/s when is close to the star and 35 km/s when it is farthest: this is in disagreement with what we said above, therefore the correct option is

E. Kepler's second law says the planet must move fastest when it is closest, not  when it is farthest away.

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You launch a ball at an angle of 35 degrees above the horizontal with an initial velocity of 38 m/s. What is the time the ball w
gayaneshka [121]

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3 years ago
Explain how to find the angle between two nonzero vectors. Choose the correct answer below. A. The angle between two nonzero vec
kozerog [31]

Answer:

θ = Cos⁻¹[A.B/|A||B|]

A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result

Explanation:

We can use the formula of the dot product, in order to find the angle between two non-zero vectors. The formula of dot product between two non-zero vectors is written a follows:

A.B = |A||B| Cosθ

where,

A = 1st Non-Zero Vector

B = 2nd Non-Zero Vector

|A| = Magnitude of Vector A

|B| = Magnitude of Vector B

θ = Angle between vector A and B

Therefore,

Cos θ = A.B/|A||B|

<u>θ = Cos⁻¹[A.B/|A||B|]</u>

Hence, the correct answer will be:

<u>A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result</u>

3 0
3 years ago
I'm not sure what equation to use.
Lelechka [254]
I would think that you would multiply then divide
7 0
4 years ago
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