Answer:
C2, C1, C4, C5 and C6 are in parallel. Therefore, we use the formula Cp = C1 + C2 + ....
Cp = C2 + C1 + C4 + C5 + C6 = ( 7 * 10 ^-3) + (18 * 10^-6) + (0.8F) + (200 * 10^-3 F) + (750 * 10^-6) = 1.008F
Now, Cp will become one capacitor and it will be aligned with C3, therefore it will now become a circuit in series.
We use the formula: 1/Cs = 1/C1 + 1/C2 + .... + ....1/Cn
Thus,
1/Cs = 1/C3 + 1/Cp
1/Cs = 1/(14 * 10^-3 F) + 1/(1.008F)
Cs = 1.4 * 10 ^-2 or if we do not round too much it will give exactly 0.0138 F
So the answer should be a)
Answer: the horizontal component of total momentum
Explanation:
Since the open cart is rolling to the left on the horizontal surface, the quantity that has the same value just before and just after the package lands in the cart is the horizontal component of total momentum.
Momentum, is the product of the mass of a particle and the velocity of the particle. The change of momentum depends on the force which acts on it. The addition of the the individual momenta is the total momentum.
Seriously this is fun dont know why u want me to enjoy this so ummmm hmmm lolololol the equation for this would be s=vif+1/2at^2 so time is lets see plug it and vell vi=0 since it started from rest so s=1/2at^2 and plug it in the displacement and time 110=1/2 a 5.21^2 and solve it and u get 8.1m/s^2
Answer:
Explanation:
Work is equal to the product of force and distance.
The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.
Substitute the values into the formula.
Multiply.
- 1 Newton meter is equal to 1 Joule
- Our answer of 157.5 N*m equals 157.5 J
<u>157.5 Joules </u> of work are done on the crate.
