All categories

3 years ago

You have a 7.04 W, 236 Ω resistor.

Physics

1 answer:

Over [174]3 years ago

3 0

Answer

the current is 0.17amps

Explanation:

This problem bothers power of an electrical circuit.

Electric power is defined as the electric heat transferred per second. This can be expressed as

P=IV

P= V²/R

P= I²R

Given data

Power p= 7.04w

Resistance R=236 ohms

Using the third equation and Substituting our data we have

7.04= I²* 236

I²= 7.04/236

I= √0.029

I= 0.17amps

You might be interested in

Which two concepts are Newton´s laws based on?

sukhopar [10]

Instantaneous impulse and continuous force: these are the foundations of Newton laws. In short explanation; concept of force and mass.

6 0

3 years ago

Read 2 more answers

a bus travels 4 km due north and 3 km due west going from bus station a to bus station b. the magnitude of the bus displacement

ladessa [460]

Answer:

5km

Explanation:

Magnitude of displacement is found by getting the resultant. Resultant is same as the bypotenuse hence

$R=\sqrt {{x^{2}+y^{2}}$ where x is the displacement in west direction and y is displacement in North direction. Substituting x with 3km and y with 4 km then

$R=\sqrt {{3^{2}+4^{2}}=5km$

4 0

3 years ago

How do lone pairs of electrons affect the bond angle differently than electrons shared in a bond?

lubasha [3.4K]

Answer:

Lone pairs cause bond angles to deviate away from the ideal bond angles

Explanation:

Bonded electrons are stabilized and clustered between the bonding electrons meaning they are much closer together. Non-bonding electrons however are not being shared between any atoms which allows them to roam a little further spreading the charge density over a larger space and therefore interfering with what would be an expected bond angle

3 0

3 years ago

How do Newton's laws of motion explain why it is important to keep the ice smooth on a hockey rink so that players can

lord [1]

Answer:

I'm not sure..but please refer to your teacher later.

Answer: Based on Newton's First law of motion (where inertia is involved), smooth ice increases the forceused to accelerate the hockey puck.

Explanation;

smooth ice reduces the resistances between the surface of the figure skates and the ice itself.
based on inertia theory ; the heavier the weight, the larger the inertia.. which explains it takes alot of force to move a heavier object than the lighter ones.. it also hard to *stop* the motion of heavier objects than the lighter ones.
now let's look at the design of the player shoe itself, they have a sharp blade at the bottom of the figure stakes.. which takes us to the law of the force.. the smaller the surface area, the more forces acting on it. So, players force (weight, F= mg) acts on the tip of the blade and on the ice
high inertia (run fast) and high force (attack opponent and pass puck) enables them to perform well in playing hockey
Thus if there's no resistance and the inertia of the player is high then they could run and pass the puck quickly

6 0

3 years ago

Read 2 more answers

A 175-kg roller coaster car starts from rest at the top of an 18.0-m hill and rolls down the hill, then up a second hill that ha

Anni [7]

Answer:

The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.

Explanation:

By Principle of Energy Conservation and Work-Energy Theorem we present the equations that describe the situation of the roller coaster car on each top of the hill. Let consider that bottom has a height of zero meters.

From top of the first hill to the bottom

$m\cdot g \cdot h_{1} = \frac{1}{2}\cdot m\cdot v_{1}^{2} +W_{1, loss}$ (1)

From the bottom to the top of the second hill

$\frac{1}{2}\cdot m\cdot v_{1}^{2} = m\cdot g \cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2}+W_{2,loss}$ (2)

Where:

$m$ - Mass of the roller coaster car, in kilograms.

$v_{1}$ - Speed of the roller coaster car at the bottom between the two hills, in meters per second.

$g$ - Gravitational acceleration, in meters per square second.

$h_{1}$ - Height of the first top of the hill with respect to the bottom, in meters.

$W_{1, loss}$ - Work done by non-conservative forces on the car between the top of the first hill and the bottom, in joules.

$v_{2}$ - Speed of the roller coaster car at the top of the second hill, in meters per seconds.

$h_{2}$ - Height of the second top of the hill with respect to the bottom, in meters.

$W_{2, loss}$ - Work done by non-conservative forces on the car bewteen the bottom between the two hills and the top of the second hill, in joules.

By using (1) and (2), we reduce the system of equation into a sole expression:

$m\cdot g\cdot h_{1} = m\cdot g\cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2} + W_{loss}$ (3)

Where $W_{loss}$ is the work done by non-conservative forces on the car from the top of the first hill to the top of the second hill, in joules.

If we know that $m = 175\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ , $h_{1} = 18\,m$ , $h_{2} = 8\,m$ and $v_{2} = 11\,\frac{m}{s}$ , then the work done by non-conservative force is:

$W_{loss} = m\cdot\left[ g\cdot \left(h_{1}-h_{2}\right)-\frac{1}{2}\cdot v_{2}^{2} \right]$

$W_{loss} = 6574.75\,J$

The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.

8 0

3 years ago