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Anettt [7]
3 years ago
13

When are Waves produced​

Physics
1 answer:
serg [7]3 years ago
7 0

Answer:

Waves are caused by wind, or are created by the friction between wind and surface water

Explanation:

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Name the process scientists use to gain knowledge about the physical world
saveliy_v [14]

The answer would be the Scientific Method.

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3 years ago
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The push up is dynamic or static​
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Answer:

Dynamic exercises

Explanation:

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When the atmosphere is not quite clear, one may sometimes see colored circles concentric with the Sun or the Moon. These are gen
stealth61 [152]

Answer:

D) diffraction

Explanation:

Corona is an optical phenomenon produced by the diffraction of sunlight or moonlight, as light moves through water droplets in the atmosphere.

This phenomenon produces one or more diffuse concentric rings of light around the Sun or Moon, usually seen as colored circles.

Therefore, the explanation for these phenomena of colored concentric circles, sometimes seen with the Sun or the Moon involves diffraction.

5 0
3 years ago
A photoelectric experiment is performed where green light with a wavelength of 546.1 nm is shined on a metal plate, creating a p
PtichkaEL [24]

Answer:

\phi=1.55 [eV]

Explanation:

We can use the work function equation for a photoelectric experiment:

\phi=\frac{hc}{\lambda}-K_{max}

  • h is the plank constant
  • c is the speed of light
  • λ is the wave length
  • K is the kinetic energy (or K=eΔV)

So we will have:

\phi=\frac{hc}{\lambda}-e\Delta V

\phi=\frac{6.63*10^{-34}*3*10^{8}}{546.1*10^{-9}}-0.728eV    

\phi=3.64*10^{-19}[J]-0.728 [eV]

\phi=(3.64*10^{-19}[J]*\frac{1eV}{1.6*10^{-19}[J]})-0.728 [eV]

\phi=2.28 [eV] - 0.728 [eV]

\phi=1.55 [eV]

I hope it helps you!

8 0
4 years ago
Read 2 more answers
German physicist Werner Heisenberg related the uncertainty of an object's position ( Δ x ) to the uncertainty in its velocity (
Ierofanga [76]

Answer:

The uncertainty in the position of the electron is 5.79x10^{-9}m

Explanation:

The Heisenberg uncertainty principle is defined as:

\Lambda p\Lambda x ≥ \frac{h}{4 \pi}  (1)

Where \Lambda p is the uncertainty in momentum, \Lambda x is the uncertainty in position and h is the Planck's constant.

The momentum is defined as:

p =mv  (2)

Therefore, equation 2 can be replaced in equation 1

\Lambda (mv) \Lambda x ≥ \frac{h}{4 \pi}

Since, the mass of the electron is constant, v will be the one with an associated uncertainty.

m \Lambda v \Lambda x ≥ \frac{h}{4 \pi} (3)

Then, \Lambda x can be isolated from equation 3

\Lambda x ≥ \frac{h}{m \Lambda v 4 \pi}  (4)

\Lambda x = \frac{6.626x10^{-34}J.s}{(9.11x10^{-31} kg)(0.01x10^{6}m/s) 4 \pi}

But 1J = Kg.m^{2}/s^{2}

\Lambda x = \frac{(6.624x10^{-34} Kg.m^{2}/s^{2}.s)}{(9.11x10^{-31} kg)(0.01x10^{6}m/s) (4 \pi)}

\Lambda x = 5.79x10^{-9}m

Hence, the uncertainty in the position of the electron is  5.79x10^{-9}m

7 0
3 years ago
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