Answer:
the answer is d I'm pretty sure
Answer: 44.57°C
Explanation:
The following can be deduced from the question:
Specific heat of water = 4.186 J/kg
From the question, we can infer that 625 × 4.186 joules of heat will be lost when there's a 1°C drop of water.
We then calculate the amount if degrees that it'll take to cool for 7.96 x 10⁴J. This will be:
= 7.96 × 10⁴ /(625 × 4.186)
= 79600/(625 x 4.186)
= 79600/2616.25
= 30.43°C
The final temperature will then be:
= 75.0°C - 30.43°C
= 44.57°C
Well it breaks it away from rain or earthqukes depends but then depostion takes the rocks away and a delta takes it into the ocean
