Answer: Theoretical mass of sodium sulphate (
) is 514.118 grams.
Explanation: For a given reaction,
![2NaOH(aq.)+H_2SO_4(aq.)\rightarrow Na_2SO_4(s)+2H_2O(l)](https://tex.z-dn.net/?f=2NaOH%28aq.%29%2BH_2SO_4%28aq.%29%5Crightarrow%20Na_2SO_4%28s%29%2B2H_2O%28l%29)
As NaOH is used in excess, therefore it is an excess reagent and
is a limiting reagent as the quantity of the product will depend on it.
We are given 355 grams of
.
Molar mass of
= 98.079 g/mol
Molar mass of
= 142.04 g/mol
1 mole of
is producing 1 mole of
, so
98.079 g/mol of
will produce 142.04 g/mol of
355 grams of
will produce =
of ![Na_2SO_4](https://tex.z-dn.net/?f=Na_2SO_4)
Mass of
= 514.118 grams
An organic compound that contains a carbonyl group with a cell wall. They are only found in plants and bacteria
Calcium chloride.
It might seem reasonable to call it calcium dichloride, but the IUPAC name for it is calcium chloride.
Answer:
0.05 M is the concentration of iodide in the solution in the test tube.
Explanation:
Molarity of KI = 0.20 M
Volume of KI solution = 2.00 mL = 0.002 L ( 1 mL = 0.001 L)
Moles of KI = n
![Molarity=\frac{\text{Moles of solute }}{\text{Volume of solution in L}}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20solute%20%7D%7D%7B%5Ctext%7BVolume%20of%20solution%20in%20L%7D%7D)
![0.20 M=\frac{n}{0.002 L}](https://tex.z-dn.net/?f=0.20%20M%3D%5Cfrac%7Bn%7D%7B0.002%20L%7D)
![n=0.20 M\times 0.002 mL =0.0004 mol](https://tex.z-dn.net/?f=n%3D0.20%20M%5Ctimes%200.002%20mL%20%3D0.0004%20mol)
Volume of solutions formed by mixing all the solutions in a test tube = V
V = 2.00 mL+1.00 mL+0.50 mL+0.50 mL+2.00 mL+2.00 mL = 8.00 ml
V = 8.00 mL = 0.008 L
Concentration of KI in the test tube = [KI]
![[KI]=\frac{0.0004 mol}{0.008 L}=0.05 M](https://tex.z-dn.net/?f=%5BKI%5D%3D%5Cfrac%7B0.0004%20mol%7D%7B0.008%20L%7D%3D0.05%20M)
![KI(aq)\rightarrow K^+(aq)+I^-(aq)](https://tex.z-dn.net/?f=KI%28aq%29%5Crightarrow%20K%5E%2B%28aq%29%2BI%5E-%28aq%29)
![[I^-]=[KI]=0.05 M](https://tex.z-dn.net/?f=%5BI%5E-%5D%3D%5BKI%5D%3D0.05%20M)
0.05 M is the concentration of iodide in the solution in the test tube.