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erik [133]
3 years ago
15

In a rocket motor fueled with butane, how many kg of liquid oxygen should be provided with each kilogram of butane to provide fo

r complete combustion
Chemistry
1 answer:
Travka [436]3 years ago
3 0
<u>Answer</u>

So this is the reaction that happens. 
<span>C4H10 + O2 = CO2 + H2O </span>

<span>Balanced, it is </span>
<span>2C4H10 + 8O2 = 8CO2 + 10H2O </span>

<span>Given 1 kg or 1000 g of butane, use stoichiometry aka factor labeling aka conversions and mole ratios to get to grams of oxygen. </span>

<span>I'll do an example. Let's form water. Hydrogen is diatomic too. </span>
<span>2H2 + O2 = 2H2O </span>

<span>Given 1000 g of Hydrogen, I need to know how many grams of oxygen to use. To convert grams to moles,
I know that 1 mol of H2 equals 2.02 g. Then, for every mole of O2, there are 2 moles of H2. Then converting moles of O2 to grams, I know that one mole of it equals 32 grams. </span>
<span>[1000 g H2] x [1 mol H2/2.02 g H2] x [1 mol O2/2 mol H2] x [32 g O2/1 mol O2] </span>

<span>My answer would be  7.9 kg </span>
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1. Coefficient

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7 0
3 years ago
For the following reaction, 5.05 grams of copper are mixed with excess silver nitrate. The reaction yields 11.0 grams of copper(
andreyandreev [35.5K]

Answer:

14.9 g is the ideal yield of Cu(NO₃)₂

Explanation:

Reactants for the reaction: Cu and AgNO₃

Products: Copper nitrate and Ag

The balanced reaction is: Cu(s) + 2AgNO₃(aq) →  2Ag (s) + Cu(NO₃)₂

As the silver nitrate is in excess, the Cu will be the limiting reagent.

We convert the mass to moles → 5.05 g . 1 mol/ 63.55 g = 0.0794 moles

Ratio is 1:1, so 0.0794 moles will produce 0.0794 moles of Cupper(II) nitrate. We convert the moles to mass, and that value will be the theoretical yield.

0.0794 mol . 187.55 g /1 mol =  of Cu(NO₃)₂

8 0
3 years ago
The average distance a gas particle travels between collisions (with the wall or another particle) is called its?
melamori03 [73]

The average distance a gas particle travels between collisions (with the wall or another particle is called the mean free path.

According to the kinetic theory of gases, the particles of a gas (atoms or molecules) have the highest kinetic energy and travel at high speeds. At standard temperature and pressure, a gas particle can reach speeds of about 470m/s.

Despite the high speeds gas particles travel, it still takes a while for the fragrance of an opened perfume to diffuse to the other end of the room. This is because when moving, the molecules do not have a free path. They constantly collide with other particles and the walls of the container and change direction randomly. The average distance a single particle can travel without colliding with other particles, or the wall of the container is called the mean free path.

To learn more about mean free path, visit:

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8 0
2 years ago
A certain sample of a liquid has a mass of 42 grams and a volume of 35 centimeters3. What is the density of the liquid? The dens
Xelga [282]

Density of liquid= \frac{mass of liquid}{volume of liquid}.

so, density of liquid= \frac{42 gm}{35 cm^{3} }= 1.2 gm/cm³.

8 0
3 years ago
Read 2 more answers
If 1 mole of gas occupies 22.4 liters of space, calculate the number of moles that will occupy 11.2 liters of space? Make sure t
Yuliya22 [10]

So, if 1 mole occupies 22.4 L, the imediate conclusion is that a bigger number of moles will occupy more than 22.4 L, and a smaller number of moles will occupy less than 22.4 L. In your case, 3 moles of gas will occupy 3 times more volume than 1 mole of gas

no need to show work i am a teacher at a college


3 0
3 years ago
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