Answer:
15.58g of CO₂ is the maximum amount that can be produced
Explanation:
The propane reacts with oxygen as follows:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
<em>Where 1 mole of propane reacts with 5 moles of oxygen</em>
To solve this question we need to find the moles of propane and oxygen to find limiting reactant using the chemical reaction:
<em>Moles propane -Molar mass: 44.1g/mol-:</em>
5.20g * (1mol / 44.1g) = 0.118 moles
<em>Moles oxygen -Molar mass: 32g/mol-:</em>
22.5g O₂ * (1mol / 32g) = 0.703 moles
For a complete reaction of 0.703 moles of oxygen are:
0.703 moles O₂ * (1mol C₃H₈ / 5mol O₂) = 0.141 moles of propane are necessaries. As there are just 0.118 moles of propane, <em>propane is limiting reactant.</em>
The moles of carbon dioxide that are produced are:
0.118 moles C₃H₈ * (3 moles CO₂ / 1 mol C₃H₈) = 0.354 moles CO₂
The maximum mass that can be produced is -Molar mass CO₂: 44.01g/mol-:
0.354 moles CO₂ * (44.01g / mol) =
15.58g of CO₂ is the maximum amount that can be produced
