Answer:
B trust me
Step-by-step explanation:
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
The answer should be $30 cause it's only 25% off
Answer: x = 9.0
Step-by-step explanation:
From the given right angle triangle,
the hypotenuse of the right angle triangle is x
With m∠39 as the reference angle,
the adjacent side of the right angle triangle is 7
The unknown side represents the opposite side of the right angle triangle.
To determine x, we would apply
the cosine trigonometric ratio which is expressed as
Cos θ = adjacent side/hypotenuse. Therefore,
Cos 39 = 7/x
x = 7/cos 39 = 7/0.777
x = 9.0 to the nearest tenth
Answer:
6ab + -3a2
Step-by-step explanation:
2ab(4a2 + 3ab - 7b2) original problem
2ab(3ab + 4a2 - 7b2) commutative property
2ab(3ab + -3a2) subtract
4 - 7 = -3
6ab + - 3a2 mulitiply
2ab x 3ab = 6ab
and that is you final expression, you can't add the last 2 numbers cause they are not like terms.
