Kc = [CS2] / [S2][C] but, since C is solid, it doesn't fit here
<span>Kc = [CS2] / [S2] </span>
<span>S2(g) + C(s) ---> CS2(g) </span>
<span>13.8mole S2 / 6.05L = 2.28M </span>
<span>Kc = x / 2.28-x </span>
<span>9.4 x (2.28-x) = x </span>
<span>21.43 - 9.4x = x </span>
<span>21.42 = 10.4x </span>
<span>x = 2.05M = [CS2] </span>
<span>2.05M x 6.05L = 12.46moles </span>
<span>12.46moles x 76gmole = 946.96g CS2</span>
Answer:5.4 g / 13.6 g *100
Explanation:Its is the correct answer
Answer : The value of acid dissociation constant is, 
Solution : Given,
Concentration pyridinecarboxylic acid = 0.78 M
pH = 2.53
First we have to calculate the hydrogen ion concentration.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
![2.53=-\log [H^+]](https://tex.z-dn.net/?f=2.53%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=2.95\times 106{-3}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D2.95%5Ctimes%20106%7B-3%7DM)
Now we have to calculate the acid dissociation constant.
The equilibrium reaction for dissociation of (weak acid) is,

initially conc. 0.78 0 0
At eqm. (0.78-x) x x
The expression of acid dissociation constant for acid is:
![k_a=\frac{[C_6H_4NO_2^-][H^+]}{[C_6H_4NO_2]}](https://tex.z-dn.net/?f=k_a%3D%5Cfrac%7B%5BC_6H_4NO_2%5E-%5D%5BH%5E%2B%5D%7D%7B%5BC_6H_4NO_2%5D%7D)
As, ![[H^+]=[C_6H_4NO_2^-]=x](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BC_6H_4NO_2%5E-%5D%3Dx)
So, 
Now put all the given values in this formula ,we get:



Therefore, the value of acid dissociation constant is, 
Answer:
The energy should be high.
Explanation:
Bonds do store energy and release it depending if it's endothermic or exothermic. The energy should be low because when a bond forms (endothermic) it releases heat, which helps form bonds. Having a high energy means the bond is absorbing energy, which helps break bonds (endothermic). How this helps!