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earnstyle [38]
2 years ago
8

If i give you a 5% sucrose solution and a 10% sucrose solution, in which is the water less concentrated?

Chemistry
1 answer:
Mnenie [13.5K]2 years ago
6 0
Of course 10% sucrose solution


sorry if im wrong
You might be interested in
Do hydrogen lose 1 2 or 3 electrons to other atoms
iren2701 [21]

Answer:<em> Hydrogen can lose as much as possible there is no limits to it.</em>

<em>Hope this helps!</em>

<em>I am joyous to assist you anytime!</em>

<em>-Jarvis</em>

<em>Extras: Hydrogen is the chemical element with the symbol H and atomic number 1. hydrogen is the lightest element in the periodic table. Hydrogen is the most abundant chemical substance in the Universe (;</em>

7 0
3 years ago
During which two minutes time period is the temperature of water changing faster?!
Vlad1618 [11]

Answer:

2-4 minutes

Explanation:

Fastest changing temperature means larger change in temperature when subtracting final temperature from initial temperature in a given time period (given time period is 2 minutes for all the options)

For 0-2 minutes, our final temperature was 40 (at 2 min) and initial temperature was  20 (at 0 min), thus temperature change was only 20 C.

For 2-4, our final temperature was 80 (at 4 min) and initial temperature was   40 (at 2 min) thus temperature change was 40 C.

For 4-6, our final temperature was 100 (at 6 min) and initial temperature was   80 (at 4 min) thus temperature change was 20 C.

We are not given temperature at 8 min so option D is invalid.

As we can clearly see that in a given 2 minute period, option B has the fastest change because it changed 40C when compared to other options that changed only 20C from starting temperature.

Hope that makes sense.

4 0
1 year ago
Suppose you have 15.0 ml of zinc. What volume of aluminum would have the same mass as the zinc?
Black_prince [1.1K]

Answer:

\large \boxed{\text{41.2 cm}^{3}}

Explanation:

1. Mass of zinc

The density of zinc is 7.14 g/cm³

D = m/V

\begin{array}{rcl}7.14 & = & \dfrac{m}{15.0}\\\\m & = & 7.14 \times 15.0\\& = & \text{107.1 g}\\\end{array}\\

2. Volume of aluminium

The density of aluminium is 2.60/cm³.

\begin{array}{rcl}2.60 & = & \dfrac{107.1}{V}\\\\2.60V & = & 107.1\\V& = &\dfrac{107.1}{2.60}\\\\& = &\textbf{41.2cm}^{\mathbf{3}}\\\end{array}\\\large \boxed{\textbf{41.2 cm}^{\mathbf{3}}}\text{ of aluminium have the same mass as 15.0 cm$^{3}$ of zinc.}

5 0
3 years ago
A sample of H2 gas (12.28 g) occupies 100.0 L at 400.0 K and 2.00 atm. A sample weighing 9.49 g occupies ________ L at 353 K and
lutik1710 [3]

Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, you know:

  • P= 2 atm
  • V= ?
  • n= 9.49 gramsx\frac{1 mole}{2 grams} = 4.745moles being 2g/mole  the molar mass of H2, that is, the amount of mass that a substance contains in one mole.
  • R= 0.082 \frac{atmL}{molK}
  • T= 353 K

Replacing:

2 atm× V = 4.745 moles× 0.082\frac{atmL}{molK}× 353 K

Solving:

V = (4.745 moles× 0.082\frac{atmL}{molK}× 353 K)÷ 2 atm

<u><em>V= 68.67 L</em></u>

Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Learn more:

  • brainly.com/question/4147359?referrer=searchResults
5 0
2 years ago
How many grams do 3.6 x10^20 atoms of silicon weigh?
creativ13 [48]
First, we divide the number of atoms of silicon given in the problem above by Avogadro's number 6.6022 x10^23. This will give us the number of moles of silicon. Then, we multiply the number of moles by the molar mass of silicon. 
number of moles = (3.6 x 10^20 atoms/6.022x10^23 atoms) = 5.97x10^-4 moles
Then, multiplying by the molar mass
                  (5.97x10^-4 moles)(28.0855 g/mol) = 0.017 grams
4 0
2 years ago
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