Both diamond and graphite are allotropes of carbon. Diamond has a high tensile strength but graphite does not.
<h3>What is a molecular model?</h3>
A molecular model is used to describe the actual behavior of a chemical compound based on the kind of bonds that exists in the molecule. Now we are talking about diamond and graphite.
Graphite is composed of hexagonal rings of carbon atoms that form layers that are held together by weak Van Der Walls forces hence they can slide over each other. This is the reason why graphite does not have a high tensile strength.
On the other hand, diamond is made up of octagonal rings of carbon atoms which are rigid and form a strong covalent network solid that explains why graphite has a high tensile strength.
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The correct answer would be the first option. Material A having a smaller latent heat of fusion would mean that it will take only less energy to phase change into the liquid phase. Latent of heat of fusion is the amount of energy needed of a substance to phase change from solid to liquid or liquid to solid.
The following observation would be included in a hypothesis: a connection between type of material and thermal energy transfer is developed (option C).
<h3>What is a hypothesis?</h3>
Hypothesis is a tentative conjecture explaining an observation, phenomenon or scientific problem that can be tested by further observation, investigation and/or experimentation.
The hypothesis is regarded as an educated guess because it predicts the possible outcome of an experiment.
The hypothesis is a statement that relates the independent variable of the experiment with the measured or dependent variable.
Therefore, the following observation would be included in a hypothesis: a connection between type of material and thermal energy transfer is developed.
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The energy range expected is 6.6 × 10^-19 J < E < 7.33 × 10^-19 J
The energy of the photon is given by;
E = hc/λ
E = energy of the photon
h = Plank's constant
c = speed of light
λ = wavelength of light
For the upper boundary range;
E = ?
h = 6.6 × 10^-34 Js
c = 3 × 10^8 m/s
λ = 270 × 10^-9
E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 270 × 10^-9
E = 7.33 × 10^-19 J
For the lower range;
E = ?
h = 6.6 × 10^-34 Js
c = 3 × 10^8 m/s
λ =300 × 10^-9
E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 300 × 10^-9
E = 6.6 × 10^-19 J
Hence, the energy range 6.6 × 10^-19 J < E < 7.33 × 10^-19 J
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