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Over [174]
3 years ago
10

Water (10 kg/s) at 1 bar pressure and 50 C is pumped isothermally to 10 bar. What is the pump work? (Use the steam tables.) -7.3

kJ/s O 7.3 kJ/s -210 kJ/s e345 kJ/s 3451 kJ/s

Chemistry
1 answer:
Andreyy893 years ago
8 0

Answer:

The pump work is 3451 kJ/s

Explanation:

Pump work (W) is calculated as

W = (h_f - h_i) \times \dot{m}

where

h_f is the enthalpy of water at its final state

h_i is the enthalpy of water at its initial state

\dot{m} = 10 kg/s is water mass flow

For liquids, properties are evaluated as saturated liquid. From the figure attached, it can be seen that

h_f = 762.81 kJ/kg

h_i = 417.46 kJ/kg

Replacing

W = (762.81 kJ/kg - 417.46 kJ/kg) \times 10 kg/s

W = 3451 kJ/s

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