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goblinko [34]
3 years ago
11

Find an equivalent fraction for each fraction? 20/100 2/8 90/100

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0
For all of them you can just simplify to their lowest fractions like this and they'll still be equivalent 2/10, 1/4, 9/10
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A copier was purchased for $12,000. Its value each year is 75% of what it was the preceding
bagirrra123 [75]

Answer:

c

Step-by-step explanation:

it will take 1.5 years, because a and b are too little. D is too much a value. C is the right answer

4 0
3 years ago
What is the average rate of change of f(x), represented by the table of values, over the interval [-3, 4]?
-Dominant- [34]
F ( -3 ) = 6
f ( 4 ) = 27
Average rate of change:\frac{27-6}{4-(-3 )}= \frac{21}{4+3}= \frac{21}{7} = 3
8 0
3 years ago
GEOMETRY PROOFS ;-;
Over [174]

Answer:

1. ae=bd; cd=ce (given) 2. ae=ac+ce (segment addition postulate) 3. bd=ac+cd (substitution property of equality) 4. ac+cd=bd (symmetric property of equality) 5. bd=bc+cd (segment addition postulate) 6. ac+cd=bc+cd (transitive property of equality) 7. ac=bc (subtraction property of equality)

i think

Step-by-step explanation:

7 0
3 years ago
Identify the vertex and the y-intercept of the graph of the function,<br> y = 0.25(x + 5)2
LUCKY_DIMON [66]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y=0.25(x+5)^2\implies y=0.25[x-(\stackrel{h}{-5})]^2+\stackrel{k}{0}~\hfill \stackrel{\textit{vertex}}{(-5,0)} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{the y-intercept occurs when x =0}~\hfill }{y=0.25(0+5)^2\implies y=0.25(5)^2}\implies y=6.25~\hfill \stackrel{\textit{y-intercept}}{(0, 6.25)}

5 0
3 years ago
Write the base number for the expression: 1.7^3​
Gemiola [76]

Answer:

i might be wrong but 4.913

Step-by-step explanation:

i got this by using the calculator  1.7^3 = 4.913

3 0
3 years ago
Read 2 more answers
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