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Effectus [21]
3 years ago
15

In his experiments on "cathode rays" during which he discovered the electron, J.J. Thomson showed that the same beam deflections

resulted with tubes having cathodes made of different materials and containing various gases before evacuation.
A) Are these observations important? Explain.
B) When he applied various potential differences to the deflection plates and turned on the magnetic coils, alone or in combination the fluorescent screen continued to show a single small glowing patch. Argue whether his observation is important.
C) Do calculations to show that the charge-to-mass ratio Thomson obtained was huge compared with that of any macroscopic object or of any ionized atom or molecule.
D) Could Thomson observe any deflection of the beam due to gravitation?
Physics
1 answer:
Andrews [41]3 years ago
8 0

Answer:

A) his observation is of little importance ,

B) This observation is very important since the movement of the point of light depends on the relationship between the already magnetic electric force

C)   see that in this second case it is 4 times less  

D) the force of gravity is of the order of 10⁻⁴⁰

therefore it is 10²⁸ times less than the electric force,

Explanation:

A) This observation is of little importance since the cacodylate ray tube always emits electrons, regardless of the material of which it is made.

B) This observation is very important since the movement of the point of light depends on the relationship between the already magnetic electric force

C) the elect's load is 1.6 10⁻¹⁹ C its mass is 9.1 10⁻³¹ kg, let's look for its relation

        e / m = 1.6 10⁻¹⁹ / 9.1 10⁻³¹

         e / m = 0.1 758 10 10¹² N

look for this in the case of an atom, let's use the lightest atom hydrogen

the homogenize have an electron of charge 1.6 10⁻¹⁹ C

and a mass of 1.6735575 10⁻²⁷ ka

        e / M = 1.6 10⁻⁻¹⁹ / 1.67 10⁻²⁷

       e / M = 0.96 10⁸ N

We see that in this second case it is 4 times less

D) the force of gravity is of the order of 10⁻⁴⁰

therefore it is 10²⁸ times less than the electric force, therefore it should not contribute to the movement of the light beam

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Objects appear different in size and shape in a container of water due to
o-na [289]

Answer:

A. refraction of light waves

Explanation:

Refraction happens when light travels from one medium to another and changes speed and bends. This also causes objects to look different sizes and shapes when they are submerged in water.

5 0
3 years ago
(i) What is the acceleration of an object between 0-4 seconds?
DENIUS [597]

Answer:

Your small tiny face

Explanation:

HIHIHIIHHI

4 0
3 years ago
A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi
vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

V=\frac {C_2V_2-C_1V_1}{C_1+C_2}

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}

Therefore

V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437

Charge, Q is given by CV hence for the first capacitor charge will be Q_1=C_1V

Here, Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C

8 0
3 years ago
17 copper wires of length l and diameter d are connected in parallel to form a single composite conductor of resistance R. What
Lubov Fominskaja [6]

Answer:

\frac{D}{d} = 4.12

Explanation:

As we know that resistance of one copper wire is given as

r = \rho \frac{L}{a}

here we know that

a = \pi (\frac{d}{2})^2

now we have

r = \rho \frac{L}{\pi (\frac{d^2}{4})}

r = \rho \frac{4L}{\pi d^2}

now we know that such 17 resistors are connected in parallel so we have

R = \frac{r}{17}

R = \rho \frac{4L}{17 \pi d^2}

Now if a single copper wire has same resistance then its diameter is D and it is given as

R = \rho \frac{4L}{\pi D^2}

now from above two equations we have

\rho \frac{4L}{\pi D^2} = \rho \frac{4L}{17 \pi d^2}

D^2 = 17 d^2

now we have

\frac{D}{d} = 4.12

3 0
3 years ago
Which of the following is NOT true of all the inner planets?
Artist 52 [7]

Hi there! :)

\large\boxed{\text{B. They are called gas giants.}}

In the solar system, we can categorize the planets as such:

Inner planets: Mercury, Venus, Earth, Mars

Outer planets: Jupiter, Saturn, Uranus, Neptune

The Inner planets are the only planets that consist of solid rock. They also do not have rings and have impact craters due to their early formation.

In comparison, all of the outer planets are primarily made up of gaseous material and contain rings.

Therefore, the correct choice is B.

7 0
3 years ago
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