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beks73 [17]
4 years ago
8

Waves keep their what even when they bounce of something

Physics
1 answer:
pentagon [3]4 years ago
7 0
The answer is shape, waves keep the same shape when bouncing off something
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Complete the sentences below using the words below, you may use each word more than once
satela [25.4K]
Decreases, stays the same, increases. The volume decreases because as air is cooled, the individual molecules collectively possess less kinetic energy and the distances between them decrease, thus leading to a decrease in the volume they occupy at a certain pressure (please note that my answer only holds under constant pressure; air, as a gas, doesn't actually have a definite volume). The mass stays the same because physical processes do not create or destroy matter. The law of conservation of mass is obeyed. You're only cooling the air, not adding more air molecules. The density decreases because as the volume decreases and mass stays the same, you have the same mass occupying a smaller volume. Density is mass divided by volume, so as mass is held constant and volume decreases, density increases.
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3 years ago
Multiply 0.00032 cm by 4.02 cm and express the answer in scientific notation
FromTheMoon [43]
0.00032cm*4.02=1.2864 × 10^-3 in scientific notation.
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Which expression shows the amount of work a 6-kilogram mass is capable of performing if it is dropped from a height of 2 meters?
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The acceleration of gravity is 9.8 m/s^2
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Short Answer
STatiana [176]

15 degrees because a glass of water won't do anything to a bath tub of 15 degree water

4 0
3 years ago
A particle moves at a constant speed in a circular path with a radius of r=2.06 cm. If the particle makes four revolutions each
nataly862011 [7]

The centripetal acceleration is 13.0 m/s^2

Explanation:

For an object in uniform circular motion, the centripetal acceleration is given by

a=\frac{v^2}{r}

where

v is the speed of the object

r is the radius of the circle

The speed of the object is equal to the ratio between the length of the circumference (2\pi r) and the period of revolution (T), so it can be rewritten as

v=\frac{2\pi r}{T}

Therefore we can rewrite the acceleration as

a=\frac{4\pi^2 r}{T^2}

For the particle in this problem,

r = 2.06 cm = 0.0206 m

While it makes 4 revolutions each second, so the period is

T=\frac{1}{4}s = 0.25 s

Substituting into the equation, we find the acceleration:

a=\frac{4\pi^2 (0.0206)}{0.25^2}=13.0 m/s^2

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

8 0
3 years ago
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