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3 years ago

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Questionson cell arrangement

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dedylja [7]3 years ago

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Which of the following is MOST useful to scientists in measuring the size of asteroids?

Alenkasestr [34]

Answer:c-The gravitational effect when spacecraft flies close to the asteriod

Explanation:

Gravitational effect on the spacecraft gives an estimate that how big is the asteroid by experiencing its gravitational pull.

The amount of extra thrust required to maintain the trajectory of the spacecraft during its motion hints at the scientist about the size of the asteroid.

Gravitational pull is directly proportional to the mass of object so greater the mass, greater will be the pull.

5 0

3 years ago

Energy released by fusion in the sun is initially in the form of

bogdanovich [222]

Energy released by fusion in the sun is initially in the form of gamma rays.

Gamma rays arise from the radioactive decay of nuclei. They are penetrating electromagnetic radiations consisting of very high energy photons.
Gamma rays are ionizing radiations and have very serious biological dangers and hazards (due to their ability of ionizing the atoms).

4 0

3 years ago

Read 2 more answers

Why should a physical quantity be measured?

Natasha_Volkova [10]

Answer:

It allows us to understand nature much more deeply than does qualitative description alone.

Explanation:

Without explaining the measurements, a quantity cannot always be measured.

Hope this helped, and please mark as Brainliest :)

8 0

2 years ago

A 3.0-kilogram cart possesses 96 joules of kinetic<br> energy. Calculate the speed of the car.

Dvinal [7]

Answer:

8.0 m/s

Explanation:

KE = ½ mv²

96 J = ½ (3.0 kg) v²

v = 8.0 m/s

5 0

3 years ago

An armada of spaceships that is 1.60 ly long (in its rest frame) moves with speed 0.800c relative to the ground station in frame

miskamm [114]

Answer:

(a). The trip take a time is 3.61 year.

(b). The trip take a time is 3.96 year.

(c). The trip take a time is 8.73 year.

Explanation:

Given that,

Length = 1.60 ly

Speed of spaceships= 0.800c

Speed of messenger = 0.910 c

(a). We need to calculate the velocity of armada

Using formula of velocity

$v'=\dfrac{v-v_{m}}{1-\dfrac{vv_{m}}{c^2}}$

Put the value into the formula

$v'=\dfrac{0.800c-0.910c}{1-\dfrac{0.800\times0.910 c^2}{c^2}}$

$v'=\dfrac{-0.11c}{1-0.800\times0.910}$

$v'=-0.404c$

We need to calculate the length

Using formula of length

$l=l'\sqrt{1-\dfrac{v'^2}{c^2}$

Put the value into the formula

$l=1.60\sqrt{1-(-0.404)^2}$

$l=1.46\ ly$

We need to calculate the length of the trip

Using formula of time

$t=\dfrac{l}{|v'|}$

Put the value into the formula

$t=\dfrac{1.46}{0.404}$

$t=3.61\ year$

(b). If the armada's rest frame

We need to calculate the length

Using formula of length

$l=l'\sqrt{1-\dfrac{v'^2}{c^2}$

Put the value into the formula

$l=1.60\sqrt{1-(0)^2}$

$l=1.60\ ly$

Using formula of time

$t=\dfrac{l}{|v'|}$

Put the value into the formula

$t=\dfrac{1.60}{0.404}$

$t=3.96\ year$

(c). If an observer in frame S

We need to calculate the length

Using formula of length

$l=l'\sqrt{1-\dfrac{v'^2}{c^2}$

Put the value into the formula

$l=1.60\sqrt{1-(0.800)^2}$

$l=0.96\ ly$

We need to calculate the time

$t=\dfrac{0.96}{0.910-0.800}$

$t=8.73\ year$

Hence, (a). The trip take a time is 3.61 year.

(b). The trip take a time is 3.96 year.

(c). The trip take a time is 8.73 year.

8 0

3 years ago