Answer:
Explanation:
From your other post, the complete question is:
"You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to the right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.
Find the sum of the force on the sled.
Determine the acceleration of the sled
.
If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?
"
Given the rope exerting a force of 50 N to the right and the snow exerts a friction force of 30 N to the left, the sum of forces
= 50 - 30
= 20N to the right
The mass of sled is 50 kg and force = mass * acceleration.
Acceleration = Force / mass
= 20 / 50 = 0.4 m/s^2 to the right
If the sled has an initial velocity 2m/s to the right, after 5 seconds it will be traveling at initial velocity + acceleration * time
= 2 + 0.4*5
= 4 m/s to the right
Unsaturated solution. It has more capacity to hold more solute.
Answer:
1.) 10.61 A
2.) 0.27 A
Explanation:
Given that a sinusoidal A.C has a maximum value of 15A.
1) What are its r.m.s values?
ii) If the time is recorded from the instant the current is zero and is becoming
positive, what is the instantaneous value of the current after 1/300s, given the
frequency is 50 Hz.
Solution.
1.)
The r.m.s current = peak current/root 2
The r.m.s current = 0.7071 × 15
The r.m.s current = 10.61 A
2.)
Given that
Time = 1/300 s
Frequency = 50 Hz
Instantaneous current can be calculated by using the formula
I = I sin wt
Where w = 2πf
Instantaneous current = 15( sin 2πft)
I = 15 × sin ( 2 × 3.143 × 50 × 1/300 )
I = 15 × sin ( 1.047 )
I = 15 × 0.01827
I = 0.27 A
Therefore, the instantaneous current is 0.27A
Answer:
V = 2.64 10⁻⁴ m³, T = 21.85 N
, T = 19.26 N
Explanation:
To calculate the cylinder volume we use the density equation
ρ = m / V
V = m / ρ
ρ = 8.44 g / cm³ (1 kg / 1000g) (10² cm / 1m)³ = 8.44 10³ kg / m³
V = 2.23 / 8.44 10³
V = 2.64 10⁻⁴ m³
We calculate the tension with Newton's second law
In the air
T-W = 0
T = mg
T = 2.23 9.8
T = 21.85 N
In water
In this case we have the push up
T + B -W = 0
T = W -B
The push formula is
B = 
g V
T = m g - g V
T = 2.23 9.8 - 1.00 103 9.8 2.64 10-4
T = 21.85 - 2.5872
T = 19.26 N
Answer:
Magnetic induction is the production of an electromotive force (voltage).
