Flow of electrons through a copper wire
Answer:
d) 1.2 mT
Explanation:
Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.
First of all, we observe that:
- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is
I = 15 A
- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).
Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by
where
is the vacuum permeability
I = 15 A is the current in the conductor
r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field
Substituting, we find:
An LDR's resistance changes with light intensity, while a thermistor's resistancce changes with temperature.
In dark, LDR's resistance is large and in the day/light LDR's resistance is small.
At low temperature, thermistor's resistance is large, while at large temperature it resistance is small.
In an LDR Resistance increases as light intensity falls, while in a thermistor resistance falls as temperature falls.
Answer:
d = 10 inch
Explanation:
The farthest distance between the centers, is along the diagonal of the rectangle. Therefore, we need to calculate the diagonal of the rectangle, but counting the fact that we have both circles.
So if, one side is 12 inch, and the other is 14 inch, we can use the Pitagoras theorem which is:
d = √(a²) + (b)²
Where a and b, are the lenght of the rectangle, but without the lenght of the diameter of both circles.
With this, the expression is this:
d = √(14 - 6)² + (12 - 6)²
d = √64+36
d = √100
d = 10 inches
Using your periodic table if you look at it 3-11 are tansition metals so the horizontal Group Number will help if the group number has to digits just remove the one so if it were to be 13, the valence would be 3, if it were 14 the valence would be ,4 if it were 15, the valence would be 5, if it were 16 the valence would be 6, if it were 17 the valence would be 7 if it were group 18 the valence would be 8 so if anymore help needed to explain hit me up
