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3 years ago

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A 65.0-kg woman steps off a 10.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 3.40 m,

what is the average resistance force exerted on her by the water

1 answer:

babymother [125]3 years ago

8 0

Answer:

19372.29 N

Explanation:

Kinetic Energy of the man = Work done by the average resistive force of water.

mg(H+d) = F×d............................ Equation 1

where, m = mass of the woman, H = Height of the platform, d = depth of water reached, F = average resistive force exerted by water.

make F the subject of the equation,

F = mg(H+d)/d...................... Equation 2

Given: m = 65.0 kg, H = 10 m, d = 3.4 m, g = 9.8 m/s²

Substitute into equation 2

F = 65(9.8)(100+3.4)/3.4

F = 19372.29 N

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A 25kg mass is suspended at the end of a horizontal, massless rope that extends from a wall on the left and from the end of a se

patriot [66]

<h2>Answer:20.97g N,32.63g N</h2>

Explanation:

We consider the forces at the knot.

The vertical forces are

$T_{2}Sin(50^{0}})$ is the vertical component of tension $T_{2}$ at the knot.

$-25g$ is the weight of the mass $25Kg$ acting downwards.

The horizontal forces are

$-T_{1}$ is the tension in the rope acting left.

$T_{2}Cos(50^{0})$ is the horizontal component of tension $T_{2}$ acting towards right.

Since the knot has no mass,it is always in equilibrium.

So,the sum of forces acting on it will be zero.

Balancing vertical forces gives,

$T_{2}Sin(50^{0}})$ $-25g=0$

$T_{2}$ = $32.63gN$

Balancing horizontal forces gives,

$T_{2}Cos(50^{0})$ $-T_{1}=0$

$T_{1}=32.63g\times Cos(50^{0})=20.97gN$

7 0

3 years ago

Read 2 more answers

A battery charger is connected to a dead battery and delivers a current of 8.9 A for 4.7 hours, keeping the voltage across the b

adell [148]

Answer:

1807.56 kJ

Explanation:

Parameters given:

Current, I = 8.9A

Time, t = 4.7hrs = 4.7 * 3600 = 16920 secs

Voltage, V = 12V

Electrical energy is given as:

E = I*V*t

Where I = Current

V = Voltage/Potential differenxe

t = time in seconds.

E = 8.9 * 12 * 16920

E = 1807056 J = 1807.056 kJ

3 0

4 years ago

Read 2 more answers

The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca

Verizon [17]

Answer:

The value is $E_i = 1.5596 *10^{-18} \ J$

Explanation:

From the question we are told that

The wavelength is $\lambda = 48.2 nm = 48.2 *10^{- 9 }\ m$

The velocity is $v = 2.371*10^6 \ m/s$

The mass of electron is $m_e = 9.109*10^{-31} \ kg$

Generally the energy of the incident light is mathematically represented as

$E = \frac{h * c}{\lambda}$

Here c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

h is the Planck constant with value $h = 6.62607015 * 10^{-34 } J\cdot s$

So

$E = \frac{6.62607015 * 10^{-34 }* 3.0 *10^{8}}{48.2 *10^{- 9 }}$

=> $E = 4.12 *10^{-18} \ J$

Generally the kinetic energy is mathematically represented as

$E_k = \frac{1}{2} * m_e * v^2$

=> $E_k = \frac{1}{2} * 9.109*10^{-31} * (2.371*10^6 )^2$

=> $E_k = 2.56 *0^{-18} \ J$

Generally the ionization energy is mathematically represented as

$E_i = 4.12 *10^{-18} - 2.56 *0^{-18}$

=> $E_i = 1.5596 *10^{-18} \ J$

7 0

3 years ago

Fluorine-18 undergoes beta-plus decay. The child isotope has an atomic mass of

ANEK [815]

Answer:

18

Explanation:

got it right on edge

4 0

3 years ago

Derive the value of electric field due to a uniform sphere of charge.

Deffense [45]

<h2>Hey there!</h2>

The Force "F" applied on the unit electric charge "q" at a point describes the electric field.

<h3>☆ Formula to find electric charge:</h3>

E = F/q

<h2>Hope it helps </h2>

4 0

2 years ago