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laila [671]
3 years ago
10

Which best describes the relationship between the direction of energy and wave motion in a transverse wave?

Physics
2 answers:
sammy [17]3 years ago
6 0
I think the correct answer from the choices listed above is the second option. The relationship between the direction of energy and wave motion in a transverse wave would be the <span>energy direction is perpendicular to the motion of the wave. Hope this answers the question. Have a nice day.</span>
Mkey [24]3 years ago
4 0

Answer: The correct option is "The energy direction is perpendicular to the motion of the wave".

Explanation:

Wave is a disturbance which carries energy from one particle to other.

When the particles of the medium travel parallel to the direction of the propagation of the wave then the wave is said to be longitudinal wave.

For example, sound wave.

When the particles of the medium travel perpendicular to the direction of the propagation of the wave then the wave is said to be transverse wave. The energy direction is perpendicular to the motion of the wave.

For example, light wave.

Therefore, the relationship between the direction of energy and wave motion in a transverse wave describes the energy direction is perpendicular to the motion of the wave.

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A plane lands on a runway with a speed of 115 m/s, moving east, and it slows to a stop in 13.0 s. What is the magnitude (in m/s2
marin [14]

Answer:

<em> The planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>

Explanation:

Acceleration: This can be defined as the rate of change of velocity. The S.I Unit of acceleration is m/s². Acceleration is a vector quantity because it can be represented both in magnitude and in direction.

Acceleration can be represented mathematically as

a = v/t.................................... Equation 1

Where a = acceleration, v = velocity, t= time.

<em>Given: v = 115 m/s, t = 13.0 s</em>

<em>Substituting these values into equation 1</em>

<em>a = 115/13</em>

<em>a = 8.846 m/s² moving east</em>

<em>Thus the planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>

4 0
3 years ago
You know your mass is 62 kg but when you stand on a bathroom scale in an elevator it says your mass is 77 kg what is the acceler
lbvjy [14]
In a stationary situation, the weight of person is
W=mg=(62 kg)(9.81 m/s^2) = 608.2 N
This is the weight "felt" by the scale, which is basically the normal reaction applied by the scale on the person, and which uses the value of g (9.81) as reference to convert the weight (602.8 N) into a mass (62 kg).

When the person is in the elevator, the scale says 77 kg. The scale is still using the same value of conversion (9.81), so the apparent weight "felt" by the scale is
W' = m'g=(77 kg)(9.81 m/s^2)=755.4 N
This is the normal reaction applied by the scale on the person, and which is directed upward. Besides this force, there is still the weight W of the person, acting downward. So, if we use Newton's second law:
\sum F = ma
W-W'=ma
where a is the acceleration of the elevator. If we solve for a, we find
a= \frac{W-W'}{m}= \frac{608.2N-755.4N}{62 kg}=-2.37 m/s^2
The negative sign means the acceleration is in the opposite direction of g (which we take positive), so it means the elevator is going upward.
4 0
3 years ago
When U-235 splits, it usually emits
Serga [27]
Splitting<span> atoms. 'Fission' is another word for </span>splitting<span>. The process of </span>splitting<span> a nucleus is called nuclear fission. ... For fission to happen, the </span>uranium-235<span> or plutonium-239 nucleus must first absorb a neutron.</span>
5 0
3 years ago
What's you favorite McDonalds Sause
LUCKY_DIMON [66]

Answer:

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5 0
3 years ago
Read 2 more answers
Two 30 uC charges lie on the x-axis, one at the origin and the other at 9 m. A third point is located at 27 m. What is the poten
alukav5142 [94]

Answer:

25000 V

Explanation:

The formula for potential is

V = Kq/r

Potential at B due to the charge placed at origin O

V1 = K q / OB

V_{1}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{27}

V1 = 10000 V

Potential at B due to the charge placed at A

V2 = K q / AB

V_{2}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{18}

V2 = 15000 V

Total potential at B

V = V1 + V2 = 10000 + 15000 = 25000 V

4 0
3 years ago
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