Answer:
Explanation:
given,
mass of seesaw,m= 50 kg
length of seesaw, d = 3 m
mass of person on one end, m₁ = 60 Kg
mass of person on another end, m₂ = 86 Kg
position of center of mass = ?
System is in equilibrium
Clockwise moment is equal to anticlockwise moment.
hence, the position of center of mass from the fulcrum is 0.78 m on 60 Kg mass side.
Answer:
first law: an object remains in uniform motion except an external force has acted upon it eg a ball in stable motion doesn't move until one moves or kicks it
second law:the body acted upon by an external force gains a momentum which is directly proportional to the applied force and acts in the direction of the force
third law: to every action there is an equal and opposite reaction eg if u push someone the person moves backward away from you and not towards you
A.) For letter a, we use the law of universal gravitation using the constant G = 6.674×10−<span>11 m3</span>⋅kg−1⋅s−<span>2
Grav. F = G*m1*m2*(1/d^2)
m1 is mass of electron = </span>9.11 × 10-31<span> kg
m2 is mass of proton = </span>1.67 × 10<span>-27 kg
d = 4.5 nm = 4.5 x 10^-9 m
Grav F = 5.01 x 10^-51 N
b.) </span>For letter b, we use the Coulomb's using the constant k = 9×10^9 N
Electric force = k*Q1*Q2*(1/d^2)
Q1 is charge of electron = -1.6 × 10-19 C
Q2 is charge of proton = +1.6 × 10-19 C
Electric force = 1.14 x 10^-11 N
