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laila [671]
3 years ago
10

Which best describes the relationship between the direction of energy and wave motion in a transverse wave?

Physics
2 answers:
sammy [17]3 years ago
6 0
I think the correct answer from the choices listed above is the second option. The relationship between the direction of energy and wave motion in a transverse wave would be the <span>energy direction is perpendicular to the motion of the wave. Hope this answers the question. Have a nice day.</span>
Mkey [24]3 years ago
4 0

Answer: The correct option is "The energy direction is perpendicular to the motion of the wave".

Explanation:

Wave is a disturbance which carries energy from one particle to other.

When the particles of the medium travel parallel to the direction of the propagation of the wave then the wave is said to be longitudinal wave.

For example, sound wave.

When the particles of the medium travel perpendicular to the direction of the propagation of the wave then the wave is said to be transverse wave. The energy direction is perpendicular to the motion of the wave.

For example, light wave.

Therefore, the relationship between the direction of energy and wave motion in a transverse wave describes the energy direction is perpendicular to the motion of the wave.

You might be interested in
The acceleration of gravity at the surface of Moon is 1.6 m/s2 . A 5.0 kg stone thrown upward on Moon reaches a height of 20 m.
kramer

Answer:

(a) 8 m/s

(b) 5 s

Explanation:

(a)

Using,

V² = U²+2gh ......................... Equation 1

Where V = final velocity, U = Initial velocity, g = acceleration due to gravity on the surface of the moon, h = height reached.

Given: V = 0 m/s ( At it's maximum height), g = -1.6 m/s² ( as its moves against gravity), h = 20 m.

Substitute into equation 1

0 = U²+[2×20×(-1.6)]

-U² = - 64

U² = 64

U = √64

U = 8 m/s.

(b)

V = U +gt.................... Equation 2

Where t = time to reach the maximum height.

Given: V = 0 m/s ( At the maximum height), g = -1.6 m/s² ( Moving against gravity), U = 8 m/s.

Substitute into equation 2

0 = 8+(-1.6t)

-8 = -1.6t

-1.6t = -8

t = -8/-1.6

t = 5 s.

5 0
3 years ago
"An alpha particle (He2+) with a velocity of 2.6x106m/scrosses a uniform magnetic field at an angle of 37.0°to the field lines a
sergey [27]

Answer:

B = 5.59x10⁹ T

Explanation:

The magnetic force (F), on a the alpha particle with charge (q) that is moving at velocity (v) as the cross product of the velocity and magnetic field (B) is:

F = qvBsin(\theta)

<u>We have:</u>

F = 1.4x10⁻³ N

v = 2.6x10⁶ m/s

θ = 37.0°

q = 2*p = 2*1.6x10⁻¹⁹ C

Hence, the strength of the magnetic field is:

B = \frac{F}{qvsin(\theta)} = \frac{1.4 \cdot 10^{-3}}{1.6 \cdot 10^{-19} C*2.6 \cdot 10^{6}*sin(37)} = 5.59 \cdot 10^{9} T

Therefore, the strength of the magnetic field is 5.59x10⁹ T.

I hope it helps you!

7 0
3 years ago
An asteroid has acquired a net negative charge of 149 C from being bombarded by the solar wind over the years, and is currently
bearhunter [10]

Answer:

93.125 × 10^(19)

Explanation:

We are told the asteroid has acquired a net negative charge of 149 C.

Thus;

Q = -149 C

charge on electron has a value of:

e = -1.6 × 10^(-19) C

Now, for us to determine the excess electrons on the asteroid, we will just divide the net charge in excess on the asteroid by the charge of a single electron.

Thus;

n = Q/e

n = -149/(-1.6 × 10^(-19))

n = 93.125 × 10^(19)

Thus, it has 93.125 × 10^(19) more electrons than protons

5 0
3 years ago
After three half-lives have elapsed, the amount of an 8.0 g sample of a radionuclide that
almond37 [142]

After three half-lives have elapsed, the amount of an 8.0 g sample of a radionuclide that remains undecayed is 1.0 g.

<h3>What is Half-Life?</h3>

Half-Life refers to the time it takes for half the amount of a substance to disappear or change.

The nucleus of the atoms of radioactive elements disintegrate to half their starting amounts after every Half-Life.

After three half-lives one-eight of the original atoms remain.

Therefore, after three half-lives have elapsed, the amount of an 8.0 g sample of a radionuclide that remains undecayed is 1.0 g.

Learn more about Half-Life at: brainly.com/question/26689704

#SPJ1

7 0
2 years ago
How are an atom of calcium-48 and an atom of calcium-47 different?
matrenka [14]
They have a different number neutrons.
8 0
3 years ago
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