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MAVERICK [17]
4 years ago
7

A planet orbits a start with the path shown below.

Physics
1 answer:
kvv77 [185]4 years ago
4 0

PART a)

As we know that gravitational potential energy is given by the formula

U = -\frac{Gm_1m_2}{r}

here we can see that gravitational potential energy inversely varies with the distance

so here when distance from the sun is minimum then magnitude of gravitational potential energy is maximum while since it is given with negative sign so its overall value is minimum at that position

So gravitational potential energy is minimum at the nearest point and maximum at the farthest point

PART b)

Since we know that sum of kinetic energy and potential energy is constant here

so the points of minimum potential energy is the point where kinetic energy is maximum which means speed is maximum

So here speed is maximum at the nearest point

Part C)

since gravitational potential energy inversely varies with distance so it's graph will be like hyperbolic graph with distance

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If you were on a decision making board with the task of choosing which innovation to fund, what criteria would you use to make y
faust18 [17]

Explanation:

The criteria for decision making would be

1. I would fund for the school of young diabetics, for the sole purpose of them leaning and being motivated for a healthy lifestyle.

2. I would also fund for new and improved insulin pumps as old ones cause multiple problems.

3 0
3 years ago
Two uniformly charged conducting plates are parallel to each other. They each have area A. Plate #1 has a positive charge Q whil
Marrrta [24]

Answer:5

Explanation:

Given

First Plate has a charge of +Q  and area A

Second Plate has a charge of -3 Q and area A

We Know electric Field due to sheet charge is given by

E=\frac{Q}{2A\epsilon }

Where Q=charge over the Plate

A=Area of plate

\epsilon= Permittivity of free space

Electric Field Due to Positive charge will always be away from it while for negative charge it is towards it.

Net Electric Field at a point between between the Plates is the superimposition of two electric with direction

E_{net}=\frac{Q}{2A\epsilon }+\frac{3Q}{2A\epsilon }

E_{net}=\frac{2Q}{A\epsilon }

Net electric Field is towards the negative charged plate

5 0
4 years ago
A 50 gram meterstick is placed on a fulcrum at its 50 cm mark. A 20 gram mass is attached at the 12 cm mark. Where should a 40 g
alekssr [168]

Answer:

The 40g mass will be attached at 69 cm

Explanation:

First, make a sketch of the meterstick with the masses placed on it;

--------------------------------------------------------------------------

               ↓                    Δ                      ↓

             20 g.................50 cm.................40g

                         38 cm                  y cm  

Apply principle of moment;

sum of clockwise moment = sum of anticlockwise moment

40y = 20 (38)

40y = 760

y = 760 / 40

y = 19 cm

Therefore, the 40g mass will be attached at 50cm + 19cm = 69 cm

              12cm             50 cm              69cm

--------------------------------------------------------------------------

               ↓                    Δ                      ↓

             20 g.................50 cm.................40g

                         38 cm                 19 cm                                              

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

5 0
3 years ago
If earth did not rotate how would air at the equator move?
Dmitry_Shevchenko [17]
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.
3 0
4 years ago
Read 2 more answers
2. Below are four velocity vs. time graphs. Which graph represents the motion of an object that
Airida [17]

Answer:

Answer (b)

Explanation:

Acceleration is the rate of change of velocity in time, therefore constant acceleration will be changing velocity in direct proportion to time and will have a linear plot on a velocity/time chart. This eliminates answer (d) which has an increasing acceleration in time

answer (a) has a negative slope so the acceleration would be considered negative

answer (c) has zero slope so acceleration is zero and velocity is constant.

answer (b) has the required positive slope and acceleration

6 0
3 years ago
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