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BARSIC [14]
3 years ago
15

Factor Polynomial 3y^2+y-14

Mathematics
1 answer:
iris [78.8K]3 years ago
4 0

Answer:

<em>Factored Form: </em><em> </em><em>( y - 2 )( 3y + 7 )</em>

Step-by-step explanation:

<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14

<em>2. Now let us break this expression into groups:  </em>

3y^2 - 6y + 7y - 14  ⇒ ( 3y^2 - 6y )( 7y - 14 )

<em>3. Factor 3y from 3y^2 - 6y:</em>

3y^2 - 6y ⇒ 3y( y - 2 )

<em>4. Factor 7 from 7y - 14:</em>

7y - 14 ⇒ 7( y - 2 )

<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>

3y( y - 2 ) + 7( y - 2 )

<em>6. Factor common term y - 2:</em>

<em>Answer: ( y - 2 )( 3y + 7 )</em>

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Answer:

You add up all the sides of the shape

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3 years ago
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A company received an invoice for$1618 dated may 11,terms 2/15 EOM what is the last date of the discount period and last date of
goldfiish [28.3K]

Answer:

last date of discount period =June 15

cash discount = $215.73

bill or amount = $1402.27

last credit date = July 5

Step-by-step explanation:

A company received an invoice for$1618 dated may 11,terms 2/15 EOM what is the last date of the discount period and last date of credit period answer with formula

a A 2/15 EOM or ending of the month means the buyer receives a  cash discount if the amount or bill is paid within a period of 15 days after the end of the month indicated May 11

EOM RESULT in the end of the discount period June 15

Total discount = 2/15 *$1618  = $215.73

Amount or bill to be paid = $1618 - $215.73 = $1402.27 on JUNE 15

last date of credit period the credit period is the period or time the buyer is given to pay the seller That is 20 days after the end of the cash discount period so the credit period last date is JULY 5

7 0
3 years ago
Ulio is running in a 13.1-mile race. There are water stops every 2.75 miles along the route from the beginning of the race. What
DerKrebs [107]

Answer:

2.1 miles

Step-by-step explanation:

Given that :

Total distance = 13.1 miles

Distance between each water stop = 2.75 miles

Distance between last water stop and end of the race

We need to find the maximum number of water stops :

Total miles / distance between water stops

13.1 / 2.75

= 4.763

Maximum number of water stops = 4

Distance to last water stop = 4 * 2.75 = 11 miles

Hence, distance between last water stop and end of Race :

Total miles - distance to last water stop

13.1 miles - 11 miles

= 2.1 miles

6 0
3 years ago
Aman has 25 marbles more than half of the marbles that Rajiv has.​If Aman has 40 marbles ,how many marbles does Rajiv have ?
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Answer:

Step-by-step explanation: lets say, rajiv has x marbles.

given: aman has 40 marbles

           and aman's marbles are 25 more than half of rajiv's marbles.

so, aman has 25 + x/2 marbles

    40 = 25 + x/2

    40 - 25 = x/2

    15 = x/2

    15*2 = x

    30 = x

thus, rajiv has 30 marbles.                  

4 0
3 years ago
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Answer:

the answer is c hope this helps have a nice day:)

Step-by-step explanation:

6 0
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