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AVprozaik [17]
3 years ago
8

Please please please please i need help with algebra 1

Mathematics
1 answer:
olga_2 [115]3 years ago
6 0
Ask away!! im all yours
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The probability distribution histogram shows the number of trees in yards in a certain neighborhood.
Vilka [71]

Answer:

45%

Step-by-step explanation:

Here, we want to know the probability of a randomly selected yard having 6 or more than 6 trees

To get this, we simply add up the probability of 6 yards and above

That is the probability of 6, 8 , 10 and 12 yards

This is obtainable from the histogram

We then proceed to add up from the graph

What we have is;

0.05 + 0.25 + 0.10 + 0.05

= 0.10 + 0.10 + 0.25 = 0.45

This is same as 45/100 which is otherwise 45%

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3 years ago
Convert from DMS (degrees, minutes, seconds) to decimal form (degrees)
tino4ka555 [31]
All I remember is:  1° (degree) = 60' (minute) = 3600" (second) and use the given numbers to put on the..... d° m' s"........dd = d + m/60 + s/3600

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same thing with 
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4 years ago
A coyote is traveling 80 feet per second. How fast is the coyote running in miles per hour?​
spin [16.1K]

54 miles per hour ......

3 0
3 years ago
How does the suffix help you understand the meaning of announcement
sergeinik [125]
The suffix 'ment' belongs to nouns that denote an action. the word 'announce' means to declare or make something known. So the word 'announcement' is the action of declaring.
6 0
3 years ago
Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha
solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

p = (0.98)^6*0.02 = 0.0177

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

Find the expected number and variance of the number of components tested before a defective component is found.

Inverse binomial distribution, with p = 0.02

Expected number before 1 defective(n = 1). So

E = \frac{n}{p} = \frac{1}{0.02} = 50

Variance is:

V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

5 0
3 years ago
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