Answer:
45%
Step-by-step explanation:
Here, we want to know the probability of a randomly selected yard having 6 or more than 6 trees
To get this, we simply add up the probability of 6 yards and above
That is the probability of 6, 8 , 10 and 12 yards
This is obtainable from the histogram
We then proceed to add up from the graph
What we have is;
0.05 + 0.25 + 0.10 + 0.05
= 0.10 + 0.10 + 0.25 = 0.45
This is same as 45/100 which is otherwise 45%
All I remember is: 1° (degree) = 60' (minute) = 3600" (second) and use the given numbers to put on the..... d° m' s"........dd = d + m/60 + s/3600
1) 118°44'15" => 118/1 + 44/60 + 15/3600 = 118.7375
same thing with
2) <span>48°30'36" => 48 + 30/60 + 36/3600 = 48.51</span>
The suffix 'ment' belongs to nouns that denote an action. the word 'announce' means to declare or make something known. So the word 'announcement' is the action of declaring.
Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with 
Expected number before 1 defective(n = 1). So

Variance is:

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.