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lutik1710 [3]
3 years ago
6

1. How are science and technology related? (1 point)

Physics
1 answer:
alina1380 [7]3 years ago
8 0

Answer:

Explanation:

1.Technology is an application of science through use of modern scientific tools.

2.They provide a concrete view of something abstract. They are also applicable to gain an understanding of better process and systems.

3.C.55.25s

4. A. straight line graph.

5. A. Milk. A pure substance consist of a single element or compound.

6.B. it has two hydrogen atom to one oxygen atom

7.B. Sugar water.

8.D.Size of their particles.

9.A.sawing a piece of wood into half.

10.A..iron changes colour when heated.

11.A.solid

12.A. Lowering the temperature, which lead to increase in gas volume according to. Boyle's law.

13.C. boiling point of naphthalene.

14.freezing,which is the mostly orderly point of water because water moves from liquid to solid state.

15.A.sublimation.

16.B.Vaporisation.

17.C.it is described by a nucleus surrounded by a large volume is space.

18. The atom in the excited state has more energy and is less stable than atom in the ground state.

19.The discovery of elements with predicted properties.

20.The sum total of mass of an element.

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:)
sweet-ann [11.9K]

Answer:

D

Explanation:

1.) The reaction is at dynamic equilibrium.

A: Nitrogen and hydrogen combine at the same rate that ammonia breaks down.

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A: Both calcium carbonate and sodium carbonate are being produced.

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2 years ago
Enterprising students set an enormous slip-n-slide (a plastic sheetcovered in water to reduce friction) on flat ground. If the s
Klio2033 [76]

Answer:

a = -0.05 m/s² (negative sign shows deceleration)

Explanation:

In order, to find out the minimum average acceleration for a student starting at 5 m/s to slide to the end, we can use 3rd equation of motion. 3rd equation of motion is given as follows:

2as = Vf² - Vi²

where,

a = minimum acceleration required = ?

s = minimum distance covered = 250 m

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Vi = Initial Velocity = 5 m/s

Therefore,

2a(250 m) = (0 m/s)² - (5 m/s)²

a = - (25 m²/s²)/(500 m)

<u>a = -0.05 m/s²</u> (negative sign shows deceleration)

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