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3 years ago

1. How are science and technology related? (1 point)

Physics

1 answer:

alina1380 [7]3 years ago

8 0

Answer:

Explanation:

1.Technology is an application of science through use of modern scientific tools.

2.They provide a concrete view of something abstract. They are also applicable to gain an understanding of better process and systems.

3.C.55.25s

4. A. straight line graph.

5. A. Milk. A pure substance consist of a single element or compound.

6.B. it has two hydrogen atom to one oxygen atom

7.B. Sugar water.

8.D.Size of their particles.

9.A.sawing a piece of wood into half.

10.A..iron changes colour when heated.

11.A.solid

12.A. Lowering the temperature, which lead to increase in gas volume according to. Boyle's law.

13.C. boiling point of naphthalene.

14.freezing,which is the mostly orderly point of water because water moves from liquid to solid state.

15.A.sublimation.

16.B.Vaporisation.

17.C.it is described by a nucleus surrounded by a large volume is space.

18. The atom in the excited state has more energy and is less stable than atom in the ground state.

19.The discovery of elements with predicted properties.

20.The sum total of mass of an element.

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Simora [160]

For the work, applicate formula:

$\boxed{\boxed{\green{\bf{W = F\times d}}}}$

According our data:

Replacing:

W = 12000 N * 1,5 m

Resolving:

W = 18000 J

The work done is <u>18000 Joules.</u>

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3 years ago

How much heat must be removed from 200 pounds of blanched vegetables at 189 degrees F to freeze them to a temperature of 22 degr

Virty [35]

To solve this problem it is necessary to apply the concepts related to heat exchange in the vegetable and water.

By definition the exchange of heat is given by

$Q =mc\Delta T$

where,

m = mass

c = specific heat

$\Delta T$ = Change in temperature

Therefore the total heat exchange is given as

$\Delta Q = Q_w+Q_v$

$\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)$

Our values are given as,

Total mass is $M_T$ = 200lb ,however the mass of solid vegetable and water is given as,

$m_v= 0.4*200lb = 80lb$

$m_w=0.6*200lb=120lb$

$T_i = 183\°F\\T_f = 22\°F\\c_w = 1Btu/lbF\\c_v = 0.24Btu/lbF$

Replacing at our equation we have,

$\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)$

$\Delta Q = (120)(1)(183-22)+(80)(0.24)(183-22)$

$\Delta Q = 22411.2Btu$

Therefore the heat removed is 22411.2 Btu

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Answer:

Explanation:

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Explanation:

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serg [7]

D. freezing, deposition, and condensation

Explanation:

In order to understand, let's see the definition of these changes of state:

- freezing: freezing occurs when a substance changes from liquid state to solid state

- deposition: deposition occurs when a substance changes from gas state to solid state, without passing through the liquid state

- condensation: this process occurs when a substance changes from gas state to liquid state

In all the three processes listed above, energy is released from the substance, which in fact loses energy. In fact:

- in a liquid, the particles have more energy than in a solid (because in liquid they can move, while in solid they can only vibrate), so during freezing, since a liquid turns into a solid, it releases energy to the surrounding

- in a gas, the particles have more energy than in a liquid (because in a gas they can move faster than in a liquid), so during condensation, since a gas turns into a liquid, energy is released to the surrounding

- in deposition, the particles change from the gas state (where they move faster) to a solid state (where they are not free to move), so they lose energy as well.

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4 years ago

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