The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:
 a)  we have four sections;
- 0 to 8 s The body is accelerating.
- 8 to 10 s The body goes at a constant speed, the acceleration is zero.
- 10 to 14 Body accelerating.
- 14 to 18 Body slowing down.
 b)  The acceleration is the first 8 s is:  a = 0.25 m / s²
 c) The maximum acceleration is:    a = 1 m / s²
 d) The displacement   is:  i) d₁ =  8m,     ii)   = 16 m
= 16 m
 e) maximum speed  is:      v = 6 m / s
Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.
         v = v₀ + a t
         y = v₀ t + ½ a t²
where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.
In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:
- Positive slope the body is accelerating and the speed is increasing.
- Negative slope the body is stopping, the speed decreases.
Let's answer the different questions about the system.
a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;
- 0 to 8 s The body is accelerating.
- 8 to 10 s The body goes at a constant speed, the acceleration is zero.
- 10 to 14 Body accelerating.
- 14 to 18 Body slowing down.
b) The acceleration is the first 8 s
           v = v₀ + a t
            
  
            
  
           a = 0.25 m / s²
c) The maximum acceleration is when the slope is maximum.
            
  
           a = 1 m / s²
Therefore the acceleration is maximum in the section between 10 and 14 s
d) The total displacement is the sum of the displacements of each section.
           
  
We look for every displacement.
        d₁ = v₀ + ½ a₁ Δt²
        d₁ = 0 + ½ 0.25 8²
        d₁ = 8 m
In the second section the velocity is constant
          d₂ = v₂ Δt₂
          d₂ = 2 (10-8)
          d₂ = 4 m
The third section.
     d₃ = v₀ + ½ a t²
     d₃ = 2 + ½ 1 (14-10) ²
     d₃ = 10 m
The distance of the fourth section.
        
we look for acceleration
           a₄ =  
  
           a₄ =  
  
           a₄ = -1.5 m / s²
      
           d₄ = 6 + ½ (-1.5) (1814) ²
           d₄ = -6 m
The total displacement is;
            = 8 + 4 + 10 -6
 = 8 + 4 + 10 -6
            = 16 m
 = 16 m
e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to
           v = 6 m / s
In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:
   a)  we have four sections;
-  0 to 8 s The body is accelerating.
- 8 to 10 s The body goes at a constant speed, the acceleration is zero.
- 10 to 14 Body accelerating.
- 14 to 18 Body slowing down.
 b)  The acceleration is the first 8 s is:  a = 0.25 m / s²
 c) The maximum acceleration is:    a = 1 m / s²
 d) The displacement   is:  i) d₁ =  8m,     ii)   = 16 m
= 16 m
 e) maximum speed  is:      v = 6 m / s
Learn more about kinematics here: brainly.com/question/24783036