The length of a rectangle is 2 more than twice the width. Find the dimensions of the rectangle if the perimeter is 76.

1 answer:

3 0

If the length of a rectangle is 2 more than twice the width, the equation for length=2x+2
width=x
perimeter=2l+2w
[2(2x+2)][2(x)]=4x+4+2x=6x+4

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9514 1404 393

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$\bf \begin{cases}
r=\textit{rate of the plane}\\
w=\textit{rate of the wind}\\
\end{cases}
\\\\

\begin{array}{ccccllll}
&distance&rate&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
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\textit{against wind}&1120&r-w&4
\end{array}
$

$\bf thus \begin{cases}
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\\\\
1120=(r-w)4\\
--------------\\
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--------------\\
thus\\
--------------\\
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\\\\
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\end{cases}
$

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