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denis-greek [22]
3 years ago
6

Please help i will give brainliest

Mathematics
2 answers:
Scilla [17]3 years ago
7 0

Answer:

x=14.4

Step-by-step explanation:

x=\sqrt{h^2-a^2} \\

x=\sqrt{28^2-24^2}

x=\sqrt{784-576}

x=\sqrt{208}

x=14.4

Harman [31]3 years ago
4 0

Answer:

The answer will be 14.4

Step-by-step explanation:

784-576 = x squared

= 208

the square root of 208 is

14.4222051

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Geometry Homework Question ​
mash [69]

Answer:

Distance is 8.485

Midpoint is (3,4)

Step-by-step explanation:

Use the points (-1,7) and (5,1)

Insert them into the equation and solve for D

D=\sqrt{x} ((5-(-1))^2 + (1-7)^2)\\D=\sqrt{x} ((6)^2 + (-6)^2)\\D=\sqrt{x} (36+36)\\D=\sqrt{x} (72)\\D=8.485

Insert points into second equation to find midpoint

(\frac{_1+5}{2} , \frac{7+1}{2}) \\(\frac{6}{2} ,\frac{8}{2} )\\(3,4)

7 0
3 years ago
Helppppp pleaseeeee fasttttt thankkkkk youuuuu
Digiron [165]
Pretty sure it is nine. I hope I helped
8 0
3 years ago
A 8 ft tall cardboard box standing next to a man casts a 20 ft shadow. If the man casts a shadow that is 15 ft long, then how ta
Nataliya [291]

Answer:

The answer is that he would be 27 ft tall

7 0
3 years ago
At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 1
chubhunter [2.5K]

So let's see here...


6:00 A.M. temperature is 33°F.

12:00 P.M temperature increased by 10°F making it 43°F.

3:00 P.M. temperature increased by another 12°F making it 55°F.

At 10:00 P.M it would decrease by 15°F making it 40°F.

The temperature would need to fall (or decrease) by 7°F to reach the original temperature of 33°F

Hope this helped!


3 0
3 years ago
Tangent 45 degrees equal to X over 100
sweet-ann [11.9K]
Tan (45)=x/100
Put tan(45) over 1 and cross multiply to get an equation
Tan (45)•100=1x
Solve for x
Tan (45)•100=161.977
5 0
3 years ago
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