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3 years ago

Please help i will give brainliest

Mathematics

2 answers:

Scilla [17]3 years ago

7 0

Answer:

x=14.4

Step-by-step explanation:

x= $\sqrt{h^2-a^2} \\$

x= $\sqrt{28^2-24^2}$

x= $\sqrt{784-576}$

x= $\sqrt{208}$

x=14.4

Harman [31]3 years ago

4 0

Answer:

The answer will be 14.4

Step-by-step explanation:

784-576 = x squared

= 208

the square root of 208 is

14.4222051

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Can someone help me with this question please

erastovalidia [21]

for 1st

use the formula of inlargement

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(2a+3)-(a-5)(2a+2)+a^2

3y(7y-8)

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4 years ago

Saturn is about 1.427 x 10^12 miles from the sun. Light travels at approximately 3 x 10^8 miles/second. How long does it take fo

CaHeK987 [17]

Answer:

4,756.66 seconds or 1.321 hours

Here's how I got that:

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2 years ago

Write an equation and answer the following plz

olasank [31]

10 divided by 5= x x=2

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3 years ago

N experiment was conducted to test the effect of a new stain remover. Twenty stains were treated with stain remover A and stain

Klio2033 [76]

Answer:

For this case the statistic calculated is $t= 1.37$

$p_v =0.17$

So the p value is a very high value and using the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and there is enough evidence to conclude that we have a difference between the two means at 10% of significance.

Step-by-step explanation:

Data given and notation

$\bar X_{A}$ represent the mean for the sample for A

$\bar X_{B}$ represent the mean for the sample B

$s_{A}$ represent the sample standard deviation for the sample A

$s_{B}=$ represent the sample standard deviation for the sample B

$n_{A}=20$ sample size for the group poisoned

$n_{B}=20$ sample size for the group unpoisoned

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the two means are equal or not , the system of hypothesis would be:

Null hypothesis: $\mu_{A} - \mu_{B} =0$

Alternative hypothesis: $\mu_{A} - \mu_{B} \neq 0$

For this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

For this case the statistic calculated is $t= 1.37$

Statistical decision

The significance level is 0.1 $\alpha=0.1$ , but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2$

The p value on this case is given

$p_v =0.17$

So the p value is a very high value and using the significance level given $\alpha=0,1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and there is enough evidence to conclude that we have a difference between the two means at 10% of significance.

5 0

3 years ago

What is the product of d – 9 and 2d2 11d – 4? 2d3 – 7d2 – 103d 36 2d3 – 7d2 – 95d 36 2d3 7d2 – 95d 36 2d3 7d2 – 103d 36.

Mice21 [21]

The product of algebraic expression is $\rm 2d^3 - 7d^2- 103d + 36$ .

We have to determine

What is the product of d - 9 and 2d^2+11d-4?

<h3>How to find the product of two algebraic expressions?</h3>

The product of the algebraic expressions is also an algebraic expression. Lastly, simplify the algebraic expression by the fundamental operations of terms for combining the like terms.

Therefore,

The product of algebraic expression is;

$\rm = (d - 9) \times (2d^2 + 11d - 4)\\\\= d (2d^2 + 11d - 4)-9 (2d^2 + 11d - 4)\\\\= 2d^3+11d^2-4d-18d^2-99d+36\\\\=2d^3 - 7d^2- 103d + 36$

Hence, the product of algebraic expression is $\rm 2d^3 - 7d^2- 103d + 36$ .

To know more about the Product click the link given below.

brainly.com/question/1337024

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2 years ago