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3 years ago

Please help i will give brainliest

Mathematics

2 answers:

Scilla [17]3 years ago

7 0

Answer:

x=14.4

Step-by-step explanation:

x= $\sqrt{h^2-a^2} \\$

x= $\sqrt{28^2-24^2}$

x= $\sqrt{784-576}$

x= $\sqrt{208}$

x=14.4

Harman [31]3 years ago

4 0

Answer:

The answer will be 14.4

Step-by-step explanation:

784-576 = x squared

= 208

the square root of 208 is

14.4222051

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3 years ago

What is the Mean,Mode and range of the set below?:

Zepler [3.9K]

Answer:

Set of numbers: 5, 6, 8, 10, 11, 15, 17, 25, 29, 29, 41, 50, 51, 52, 52, 54, 56, 57, 57

Mean: 32.89

Median: 29

Mode: 29, 52, 57

Range: 52

Step-by-step explanation:

The numbers are already ordered for us, so to find the mean, we need to add the numbers and divide the sum by the number of numbers. This gives us about 32.89.

The median is the middle number in the set, so right in the middle of the set is 29.

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Happy learning and sorry for the late answer!

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7 0

3 years ago

Read 2 more answers

You kept track of the numbr of minutes you spent on homework for one week. 18, 20, 22, 11, 19, 18, 18 What is range of minutes y

frosja888 [35]

Answer:

your range is 11

Step-by-step explanation:

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4 0

3 years ago

Help please, thank you! :)

gayaneshka [121]

I think it would be 100°

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3 years ago

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given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago