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Doss [256]
3 years ago
14

Which of the following is equivalent to log 7^ 50 rounded to three decimal places?

Mathematics
1 answer:
otez555 [7]3 years ago
4 0
7^50
= 1.798 × 10^42

i am a mathematics teacher. if anything to ask please pm me
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Maurinko [17]

Answer:

Number of tickets- 1,4,7,8,10

Charge($)- 9,36,63,72,90

Step-by-step explanation:

5 0
2 years ago
Record the data on a line plot 20,17,20,17,18,17,20,18,16
jek_recluse [69]

Answer:

ex or x times y

Step-by-step explanation:

vdjxrjs bc sgshxrhx

5 0
4 years ago
Read 2 more answers
How do you simplify this and write as a polynomial in standar form? (x-9)3x-7)+(3x^2-5x+2)​
nasty-shy [4]

Answer:

Standard form of (x-9)(3x-7) + (3x^{2} - 5x+2) =6x^{2}  - 39x + 65

Step-by-step explanation:

Here, the given expression is (x-9)(3x-7) + (3x^{2} - 5x+2)

Now, simplifying the above expression in parts, we get

(x-9)(3x-7) = 3x^{2}  - 7x -27x + 63 = 3x^{2}  - 34x + 63

hence, combining both parts:

(x-9)(3x-7) + (3x^{2} - 5x+2)=(3x^{2}   -34x +63) + (3x^{2} - 5x+2)

= 6x^{2}  - 39x + 65

The above expression is of the STANDARD FORM: ax^{2}  +bx + c

Hence, the standard form of (x-9)(3x-7) + (3x^{2} - 5x+2) =6x^{2}  - 39x + 65

6 0
4 years ago
What is the value of x in equation (-35)^x = 1
FinnZ [79.3K]

Answer:

x = 0.

Step-by-step explanation:

(-35)^x = 1

Now any number to the power 0 is 1.

So x = 0.

5 0
4 years ago
Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv
aalyn [17]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

Estimated life = 5 years

Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = \frac{\textup{82,000-4,000}}{\textup{5}}

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

= $46,800

Thus,

The book value at the beginning of year 4

= Purchasing cost - Depreciation

= $82,000 - $46,800

= $35,200

Now,

The remaining life = Revised estimated life - Years passed

= 8 - 3

= 5 years

therefore,

Depreciation expense =\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}

= \frac{\textup{35,200  - 4000}}{\textup{5}}

= $6,240

Hence,

The correct answer is option (a) $6,240

7 0
3 years ago
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