Answer:
x = 1± 3i
Step-by-step explanation:
x^2-2x+10=0
We can complete the square to solve by subtracting 10 from each side
x^2-2x+10-10=-10
x^2 -2x = -10
We need to add (2/2) ^2 to each side or 1
x^2 -2x+1 = -10 +1
x^2 -2x+1 = -9
The left side factors into (x- (2/2) ) ^2
(x-1) ^2 = -9
Take the square root of each side
sqrt((x-1) ^2 =± sqrt(-9)
x-1 = ±sqrt(-1) sqrt(3)
Remember the sqrt(-1) = i
x-1 = ± 3i
Add 1 to each side
x-1+1 = 1± 3i
x = 1± 3i
Areaa= 0.5 b h
= 0.5 x 9 x 6 = 27 mm
(x-h)²+(y-k)²=r² is the equation of a circle with radius of r
so if x-h=4 and y-k=3 then
4²+3²=r²
16+9=r²
25=r²
sqrt both sides
5=r
radius is 5 units
You mean to simplify as this is an expression not an equation, as it has no equal sign...
Factor our 4 first
(4r^3t^2)/(-rt)
Now factor out -rt
-4r^2t
