What does it mean that a form of energy might take more energy to harness than it provides? Are renewable resources always renew
1 answer:
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Answer:
x = 12cm
Explanation:
First, with the values given for the force and the displacement, you calculate the spring-constant of the dynamometer by using the following equation (primero, con los valores dados de la fuerza y el desplazamiento, calculas la constante del resorte aplicando la siguiente formula):
F: force (fuerza) = 10N
k: spring constant (constante del resorte)
x: displacement of the spring (desplazamiento del resorte) = 6cm
by using these values you calculate k (usando estos valores calculas k):
With this value you calculate the displacement for a force of 20N (con este valor de k calculas el desplazamiento del resorte para una fuerza de 20N):
hence, the displacement is 12cm
Answer:
(A) 4.09 kg/s
(B) 589.9 m/s
(C) 0.0008707 m^{3} = 8.71 cm^{2}
Explanation:
inlet pressure of steam (P1) = 4 MPa
inlet temperature of steam (T1) = 400 degree celcius
inlet velocity (V1) = 60 m/s
outlet pressure (P2) = 2 MPa
outlet temperature (T2) = 300 degree celcius
inlet area (A1) = 50 cm^{2} = 0.005 m^{2}
rate of heat loss (Q) = 75 kJ/s
(A) mass flow rate (m) = \frac{A1 x V1}{α1}
where the initial specific volume (α1) for the given temperature and pressure is gotten from tables A-6 = 0.07343 m^3/kg
m = \frac{0.005 x 60}{0.07343}
m = 4.09 kg/s
(B) we can get the outlet velocity using the energy balance equation
E in = E out
m(h1 + \frac{(V1)^{2}}{2}) = m(h2 + \frac{(V2)^{2}}{2})
V2 =
where h1 and h2 are the enthalpies and are gotten from table A-6
V2 =
V2 = 589.9 m/s
(C) the outlet area is gotten from mass flow rate (m) = \frac{A2 x V2}{α}
A2 = (α2 x m) / V2
where the initial specific volume (α2) for the given temperature and pressure is gotten from tables A-6 = 0.12552 m^3/kg
A2 = (0.12552 x 4.09) / 589.5 = 0.0008707 m^{3} = 8.71 cm^{2}
Answer:
(a)
(b)
Explanation:
It is given that,
Force acting on the particle, F = 12 N
Displacement of the particle,
Magnitude of displacement,
(a) If the change in the kinetic energy of the particle is +30 J. The work done by the particle is given by :
is the angle between force and the displacement
According to work energy theorem, the charge in kinetic energy of the particle is equal to the work done.
So,
(b) If the change in the kinetic energy of the particle is (-30) J. The work done by the particle is given by :
Hence, this is the required solution.