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3 years ago

If you wanted to detect x rays coming from the sun, where would you place the detector? Why?

2 answers:

4 0

You would have to place your sensor above earth's atmosphere because it blocks out nearly all x-rays. this is why we have the Chandra observatory

hope this helps

Nady [450]3 years ago

3 0

If you wanted to detect X-rays coming from the sun, the detector would have to be placed in orbit around Earth since most X-rays are absorbed the atmosphere.

Hope this helped :)

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Air in the amount of 2 lbm is contained in a well-insulated, rigid vessel equipped with a stirring paddle wheel. The initial sta

vladimir1956 [14]

Explanation:

It is known that energy balance relation is as follows.

$\Delta E_{system} = E_{in} - E_{out}$

Also, $W_{in} = \Delta U$

so, $W_{in} = mC_{v}(T_{2} - T_{1})$

According to the ideal gas equation,

$T_{2} = T_{1} \frac{P_{2}}{P_{1}}$

Putting the values into the above equation as follows.

$T_{2} = T_{1} \frac{P_{2}}{P_{1}}$

= $(520R) \frac{40psia}{30psia}$

= 693.3 R

Now, we will convert the temperature into degree Fahrenheit as follows.

693.3 - 458.67

= $234.63^{o}F$

From table A- $2E_{a}$

$C_{p}$ = 0.240 Btu/lbm R and $C_{v}$ = 0.171 Btu/lbm

Now, we will substitute the energy balance as follows.

$W_{in} = mC_{v}(T_{2} - T_{1})$

= $2 lbm \times 0.171 Btu/lbm R (693.3 - 520)$

= 59.3 Btu

Thus, we can conclude that final temperature of air is 59.3 Btu.

6 0

4 years ago

When the researchers connected the solution-filled glass plates of the flow chamber to the AC generator, the ITO-coated plates m

Aleks [24]

Answer:

A capacitor

Explanation:

From experimental findings,the plates are connected to a 10Hz ac generator and a potential difference of 1.5V.The ITO is a transplant conducting material,charges accumulates on it when a voltage is applied to it.Exactly what is seen on a parallel plate capacitor

6 0

3 years ago

A sled and rider (combined mass of 69 kg) finish a downhill run with a speed of 30 m/s, then enter a flat (horizontal) area wher

NARA [144]

Answer:

Distance that sled move while slowing down= 195.65m

Explanation:

Distance traveled by sled after slowing down=S

acceleration at the start= -2.3 m/s2

initial speed u=30m/s

final speed=v

By using the equation