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3 years ago

If you wanted to detect x rays coming from the sun, where would you place the detector? Why?

2 answers:

4 0

You would have to place your sensor above earth's atmosphere because it blocks out nearly all x-rays. this is why we have the Chandra observatory

hope this helps

Nady [450]3 years ago

3 0

If you wanted to detect X-rays coming from the sun, the detector would have to be placed in orbit around Earth since most X-rays are absorbed the atmosphere.

Hope this helped :)

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An airplane is traveling at an altitude of 15,490 meters. A box of supplies is dropped from its cargo hold. What is the cargo's

topjm [15]

Answer :

556.59 m/s.

Explanation:

Given that,

An airplane is traveling at an altitude of 15,490 meters.

A box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.

The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :

$v^2-u^2=2as$

Put u = 0 and a = g

$v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s$

So, when it hits the ground its velocity is 556.59 m/s.

8 0

3 years ago

Which poison was used in the Jonestown massacre?

olga nikolaevna [1]

That would be Cyanide.

Hope this helps! (:

3 0

3 years ago

Read 2 more answers

hen a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant

Sladkaya [172]

Answer:

Incomplete question

Complete question:

a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 44kg , the acceleration of the object is 4m/s². If the same force acts upon another object whose mass is 11kg what is this object's acceleration?

Answer: 8m/s²

Explanation:

From the statement we deduced that acceleration varies inversely with mass where force was kept constant.

Therefore,

F/m = a or F = ma

For the first statement, substituting the mass and acceleration gives:

F = 44 x 4 = 88N

Applying the force above to the second mass gives us:

a = 88/11 = 8m/s²

3 0

3 years ago

if a diffraction grating produces a third-order bright spot for red light (of wavelength 650 nm ) at 68.0 ∘ from the central max

Mashutka [201]

Answer:

The angle is 25.34°.

Explanation:

Given that,

Wave length = 650 nm

Angle = 68.0°

We need to calculate the distance

For a diffraction grating

$d\sin\theta=m\lambda$

$d=\dfrac{2\times650\times10^{-9}}{\sin68.0}$

$d=2.10\times10^{-6}\ m$

We need to calculate the angle

Using formula for angle

$d\sin\theta=m\lambda$

$\sin\theta=\dfrac{m\times\lambda}{d}$

$\sin\theta=\dfrac{2\times450\times10^{-9}}{2.10\times10^{-6}}$

$\sin\theta=25.34^{\circ}$

Hence, The angle is 25.34°.

8 0

3 years ago

A packing crate slides down an inclined ramp at constant velocity. Thus we can deduce thatA) a frictional force is acting on itb

torisob [31]

Answer:

A) a frictional force is acting on it

Explanation:

The crate is sliding down the inclined ramp at constant velocity: constant velocity means zero acceleration, a = 0. According to Newton's second law:

F = ma

this also means that the net force acting along the direction of the slope is zero.

Without frictional force, there would be only one force acting along this direction: the component of the weight of the crane parallel to the slope, acting downward:

$W_p = mg sin \theta$

where $\theta$ is the angle of the incline. Therefore, the net force along this direction would not be zero. In order to have a net force of zero, there must be another force acting upward on the crate: and the only force that is possibly acting on the crate against its direction of motion is the frictional force, whose magnitude must be equal to $W_p$ , in order to produce a net force of zero (and therefore, a zero acceleration).

8 0

4 years ago